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FromTheMoon [43]
2 years ago
9

GUYS HELP ASAP CHECK THE ATTACHED PHOTO

Mathematics
1 answer:
ASHA 777 [7]2 years ago
7 0

Answer:

As they triangles are congruent, we can say that, angle A = angle O

So, angle A = 105+25 =130

A = 180 - 130 = 50° all angles in a triangle add up to 180)

Soo 50° is the answer,

I'm not too sure about it but I think this is correct, hope this helps, correct me if I'm wrong....

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Two students are preparing for a marathon. Hector ran 8 miles in 85 minutes. Mario ran 6 miles in 55 minutes. Who has the faster
Stels [109]
formula\ for\ average\ speed= \frac{distance}{time}\\\\
Hector:\\\\
v_H=\frac{8miles}{85\ minutes}\approx0,09\frac{mile}{min}\\\\
Mario:\\\\
v_M=\frac{6miles}{55minutes}=0,1\frac{miles}{min}\\\\
Mario\ has\ faster\ speed.
7 0
2 years ago
Read 2 more answers
1. Find the common difference of the sequence: 31, 26, 21, 16, ...
hichkok12 [17]

Answer:

it is subtract 5

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
A quality control expert at LIFE batteries wants to test their new batteries. The design engineer claims they have a variance of
iris [78.8K]

Answer:

The probability that the mean battery life would be greater than 533.2 minutes (in a sample of 75 batteries) is \\ P(z>0.48) = P(x>533.2) = 0.3156

Step-by-step explanation:

The main thing we have to take into account in this question is that we are about to find the probability of a <em>sample mean</em>. The distribution for <em>sample means</em> follows a <em>normal distribution</em> with mean \\ \mu and standard deviation \\ \frac{\sigma}{\sqrt{n}}. Mathematically

\\ \overline{x} \sim N(\mu, \frac{\sigma}{\sqrt{n}})

For values of the sample \\ n \ge 30, no matter the distribution the data come from.

And the variable <em>z</em> follows a <em>standard normal distribution</em>, and, as we can remember, this distribution has a mean = 0 and a standard deviation = 1. Mathematically

\\ z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}} [1]

That is

\\ z \sim N(0, 1)

We have a variance of 3364. That is, a <em>standard deviation</em> of

\\ \sigma^2 = 3364; \sigma = \sqrt{3364} = 58

The population mean is

\\ \mu = 530

The sample size is \\ n = 75

The sample mean is \\ \overline{x} = 533.2

With all this information, we can solve the question

The probability that the mean battery life would be greater than 533.2 minutes

Using equation [1]

\\ z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}

\\ z = \frac{533.2 - 530}{\frac{58}{\sqrt{75}}}

\\ z = \frac{3.2}{\frac{58}{8.66025}}

\\ z = \frac{3.2}{6.69726}

\\ z = 0.47780

With this value of z we can consult a <em>cumulative standard normal table</em> (or use some statistic program) to find the cumulative probability for <em>z</em> (and remember that this variable follows a standard normal distribution).

Most standard normal tables have values for z for only two decimals, so we can round the previous value for z as z = 0.48.

Then

\\ P(z

However, in the question we are asked for \\ P(z>0.48) = P(x>533.2). As well as all normal distributions, the standard normal distribution is symmetrical around the mean, and we have

\\ P(z>0.48) = 1 - P(z

Thus

\\ P(z>0.48) = 1 - 0.68439

\\ P(z>0.48) = 0.31561

Rounding to four decimal places, we have

\\ P(z>0.48) = 0.3156

So, the probability that the mean battery life would be greater than 533.2 minutes is (in a sample of 75 batteries) \\ P(z>0.48) = P(x>533.2) = 0.3156.

5 0
3 years ago
NEED ANSWERS FASSSTTT!!
goblinko [34]

Answer:

answer c)

Step-by-step explanation:

Hope this helps you out

5 0
2 years ago
A jogger runs 6 miles per hour faster downhill than uphill. If the jogger can run 5 miles downhill in the same time that it take
muminat

Answer:

The speed of jogger in uphills is 4 mile per hour  

And  The speed of jogger in downhills is 10 mile per hour

Step-by-step explanation:

Given as :

The distance cover by jogger in downhill (Dd) = 5 miles

The distance cover by jogger in uphill     (Du)  = 2 miles

The time taken by jogger in downhill       (Td)  = T  hour

The time taken by jogger in uphill            (Tu)  = T hour

Let The speed of jogger in uphills            (Su)  = x mph

So ,The speed of jogger in downhills      (Sd)  =( x + 6 ) mph

∵, Time = \frac{Distance}{Speed}

So, Tu = \frac{Du}{Su}

Or, T = \frac{2}{x}   h

And Td = \frac{Dd}{Sd}

Or,   T = \frac{5}{(x + 6)}  h

∵  Time duration of both is same

∴  \frac{2}{x} = \frac{5}{(x + 6)}

Or,  2 × (x + 6) = 5x

Or,  2x + 12 = 5x

So,    12 = 3x

∴       x = \frac{12}{3} = 4 mph

And  x + 6 = 4 + 6 = 10 mph

Hence The speed of jogger in uphills is 4 mile per hour  

And      The speed of jogger in downhills is 10 mile per hour   Answer

5 0
3 years ago
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