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Wittaler [7]
3 years ago
9

Solve 200m-125m+48,250=51,250-175m​

Mathematics
1 answer:
earnstyle [38]3 years ago
3 0

Answer:

The answer is m=12

Step-by-step explanation:

1.) combine like terms on both sides of the equation.

2.) After all like terms are combined, divide 250 from both sides.

3.) m=12

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Complete the square to rewrite y = x^2 + 6x + 3 in vertex form. Then state whether the vertex is a maximum or a minimum and give
bixtya [17]

Answer:

Let's complete the square first.

y = x² + 6x + 3

  = (x² + 6x + 9) - 6

  = (x + 3)² - 6

Therefore, the vertex is (-3, -6) and since the coefficient of (x + 3)² is positive, the vertex is a minimum.

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2 years ago
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Use a linear approximation (or differentials) to estimate the given number. (Round your answer to five decimal places.) 3 217
Soloha48 [4]

Answer:

f(216) \approx 6.0093

Step-by-step explanation:

Given

\sqrt[3]{217}

Required

Solve

Linear approximated as:

f(x + \triangle x) \approx f(x) +\triangle x \cdot f'(x)

Take:

x = 216; \triangle x= 1

So:

f(x) = \sqrt[3]{x}

Substitute 216 for x

f(x) = \sqrt[3]{216}

f(x) = 6

So, we have:

f(x + \triangle x) \approx f(x) +\triangle x \cdot f'(x)

f(215 + 1) \approx 6  +1 \cdot f'(x)

f(216) \approx 6  +1 \cdot f'(x)

To calculate f'(x);

We have:

f(x) = \sqrt[3]{x}

Rewrite as:

f(x) = x^\frac{1}{3}

Differentiate

f'(x) = \frac{1}{3}x^{\frac{1}{3} - 1}

Split

f'(x) = \frac{1}{3} \cdot \frac{x^\frac{1}{3}}{x}

f'(x) = \frac{x^\frac{1}{3}}{3x}

Substitute 216 for x

f'(216) = \frac{216^\frac{1}{3}}{3*216}

f'(216) = \frac{6}{648}

f'(216) = \frac{3}{324}

So:

f(216) \approx 6  +1 \cdot f'(x)

f(216) \approx 6  +1 \cdot \frac{3}{324}

f(216) \approx 6  + \frac{3}{324}

f(216) \approx 6  + 0.0093

f(216) \approx 6.0093

6 0
3 years ago
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Iteru [2.4K]

Answer:

Parameter                                                                                

Step-by-step explanation:

Parameter and statistic:

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Population of interest:

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adelina 88 [10]

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Then,

(0.25 mg/min ) (0.5/0.5) = 0.125 mg/ 0.5 min (0.125 mg per half minute)

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Answer:

Yes

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