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inessss [21]
3 years ago
14

A designated hitter made 8 hits in 10 games. find the ratio of hits to games

Mathematics
2 answers:
snow_tiger [21]3 years ago
6 0
Answer: 4:5

Explanation:
hits to games
8 hits 10 games
8:10
divide by 2
4:5
avanturin [10]3 years ago
5 0

Answer:

4:5

Step-by-step explanation:

reduce the 8 and 10 by dividing both by 2.

You might be interested in
Let the universal set be the set of integers and let A = {x | x^2 ≤ 5}. Write A using the roster method.
Zarrin [17]

Answer:

Step-by-step explanation:

Given that Z the set of integers is the universal set and

A is given in set builder form.

A = {x | x^2 ≤ 5}

To convert this into roster form, we can find solutions for x

When x^2\leq 5\\|x|\leq \sqrt{5} =2.236

i.e. all integers lying between -2.236 and 2.236

The only integers satisfying this conditions are

-2,-1,0,1,2

Hence A in roster form is

A={-2,-1,0,1,2}

8 0
3 years ago
What is 5/6 times 120 =
Dominik [7]
Answer: you can use take out the 5 and multiply 5 by 120=600.then take out the 6 and multiply 6 by 120=720.then take 600 and 720,put it into a fraction.
6 0
3 years ago
A powder diet is tested on 49 people, and a liquid diet is tested on 36 different people. Of interest is whether the liquid diet
brilliants [131]

Answer:

There is not enough evidence to support the claim that the liquid diet yields a higher mean weight loss than the powder diet (P-value = 0.15).

Step-by-step explanation:

This is a hypothesis test for the difference between populations means.

The claim is that the liquid diet yields a higher mean weight loss than the powder diet.

Then, the null and alternative hypothesis are:

H_0: \mu_1-\mu_2=0\\\\H_a:\mu_1-\mu_2< 0

The significance level is 0.05.

The sample 1 (powder diet group), of size n1=49 has a mean of 42 and a standard deviation of 12.

The sample 2 (liquid diet group), of size n2=36 has a mean of 45 and a standard deviation of 14.

The difference between sample means is Md=-3.

M_d=M_1-M_2=42-45=-3

The estimated standard error of the difference between means is computed using the formula:

s_{M_d}=\sqrt{\dfrac{\sigma_1^2}{n_1}+\dfrac{\sigma_2^2}{n_2}}=\sqrt{\dfrac{12^2}{49}+\dfrac{14^2}{36}}\\\\\\s_{M_d}=\sqrt{2.939+5.444}=\sqrt{8.383}=2.895

Then, we can calculate the t-statistic as:

t=\dfrac{M_d-(\mu_1-\mu_2)}{s_{M_d}}=\dfrac{-3-0}{2.895}=\dfrac{-3}{2.895}=-1.04

The degrees of freedom for this test are:

df=n_1+n_2-1=49+36-2=83

This test is a left-tailed test, with 83 degrees of freedom and t=-1.04, so the P-value for this test is calculated as (using a t-table):

\text{P-value}=P(t

As the P-value (0.15) is greater than the significance level (0.05), the effect is not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that the liquid diet yields a higher mean weight loss than the powder diet.

6 0
3 years ago
Read 2 more answers
PLEASE HELP!
Nadya [2.5K]

Answer: no solution or zero solutions.

Step-by-step explanation:

8 0
3 years ago
Can anyone help me ??
bogdanovich [222]
The answer is B 1 =52 2=66
8 0
3 years ago
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