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Yuki888 [10]
3 years ago
13

You have a recipe that indicates to use 3 parts milk for every 2 parts sugar You use 12 cups of milk How much sugar do you need

Mathematics
1 answer:
Stells [14]3 years ago
8 0
Proportion
3 parts milk. 12cups
2 parts sugar X

8 cups sugar

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Zoey is designing a jewelry box in the shape of a rectangular prism. The base is 6 inches by 5 inches and the height is 4 inches
makvit [3.9K]

Answer:

148 square inches

Step-by-step explanation:

Step 1: finding the area of the base (upper base plus lower base)

        2( L x W).                  

      2 (6in. x 5in.)

      2( 30 square inches.)

      60 square inches

Step 2: finding the area of first 2 sides

     2 ( l x w)

   2 ( 5in x 4in)

  2 ( 20 square inches.)

     40 square inches

step 3: finding the area of the last 2 sides

  2(lxw)

  2(4in.x 6in.)

 2(24 square inches.)

  48 square inches

step 4: combine all the answers.

60 square inches. + 40 square inches. + 48 square inches = 148 square inches

7 0
3 years ago
Read 2 more answers
The difference between three times a number and 15 is equal to 6. Find the number
andreyandreev [35.5K]
15+6=21
21÷3=7
answer
3×7-15=6
5 0
3 years ago
Your deck is 3 2/3 feet off
Irina-Kira [14]

Your deck is bigger because it’s 3 and 2/3 and your neighbor is 3 and 8/9 your deck is bigger because 2/3 are bigger then 8/9

6 0
2 years ago
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Find the equation of the line that passes through (3,-4) and is parallel to 3x+y+2=0
miskamm [114]

Answer:

y=-3x+5

Step-by-step explanation:

it parallel to 3x+y+2=0 => line is: 3x+y+c=0

It through (3;-4) => 3(3)+(-4)+c=0 <=> c=-5

Line is 3x+y-5=0 => y=-3x+5

4 0
2 years ago
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Ashley and Kristin are selling wrapping paper for a school fundraiser. Customers can buy rolls of plain wrapping paper and rolls
rodikova [14]

The cost of one roll of plain wrapping paper is $5 and one roll of shiny wrapping paper costs $16.

Step-by-step explanation:

Step 1; Assume that the cost of one roll of plain wrapping paper is $x and a roll of shiny wrapping paper costs $y. so we have the following equations from the given data

4x + 3y = 68, take this as equation 1.

9x + 2y = 77, take this as equation 2

Step 2; We multiply equation 1 with 2 and equation 2 with 3 so we can cancel out the variable y in both equations. By doing this we get

8x + 6y = 136, take this as equation 3,

9x + 2y = 77, this is equation 4.

If we subtract 4 from 3, we cancel out the y variable and can calculate the value of x.

-19x = -103 , x = \frac{-95}{-19} = 5.

Step 3; Substituting this value of x in any of the previous equations we will get x's value. Here this value of y is substituted in equation 1.

4 (5) + 3y = 68, 20 + 3y = 68 , 3y = 48, y= 16.

So we have x = $5 and y = $16.

5 0
2 years ago
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