Answer:
Length:8 m
Width:3 m
Step-by-step explanation:
<u><em>The complete question is</em></u>
If the perimeter of a rectangle is 22 meters, and the perimeter of a right triangle is 12 meters (the sides of the triangle are half the length of the rectangle, the width of the rectangle, and the hypotenuse is 5 meters). How do you solve for L and W, the dimensions of the rectangle.
step 1
<em>Perimeter of rectangle</em>
we know that
The perimeter of rectangle is equal to

we have

so

Simplify
-----> equation A
step 2
Perimeter of triangle
The perimeter of triangle is equal to


so

Multiply by 2 both sides

----> equation B
Solve the system of equations by graphing
Remember that the solution is the intersection point both graphs
using a graphing tool
The solution is the point (8,3)
see the attached figure
therefore
The dimensions of the rectangle are
Length:8 m
Width:3 m
Answer:
WHATS THE QUESTION
Step-by-step explanation:
???rrtrttt r the r
Answer:
C.
Step-by-step explanation:
First, lets find the y-intercept. The y-intercept where the line passes through the y-axis. In this case, it is -3.
Now, to find the slope, lets find the next non-decimal point(that way it is easier on us). That would be (1,-1). Now, to get to this point from the y-intercept, we have to go left 1 unit, and up 2 units. So, the change in y over change in x = 2/1 or 2. Now, using this information, we can form the equation:
y = 2x + -3. or y = 2x - 3.