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Anestetic [448]
3 years ago
7

Martin won first place in the 100-meter dash with a time of 14 23/100 seconds.Samuel came in second place with a time of 15 7/10

seconds. By how many hundredths of a second did martin beat Samuel?
Mathematics
2 answers:
ohaa [14]3 years ago
8 0

Answer: The answer is 47th of 100 of a second.


Step-by-step explanation:  Given that in the 100-metre dash, Martin won first place by taking a time of

M_t=14\dfrac{23}{100}=\dfrac{1423}{100}~\textup{seconds}.

And, Samuel came second by taking time of

S_t=15\dfrac{7}{10}=\dfrac{157}{10}~\textup{seconds}.

The difference between the time of arrival of Martin and Samuel is given by

t=S_t-M_t=\dfrac{157}{100}-\dfrac{1423}{100}=\dfrac{47}{100}.

Thus, Martin beat Samuel by forty seven - hundredth of a second.



nasty-shy [4]3 years ago
4 0

Answer:

Martin meats Samuel by 147humdreth of a second

Step-by-step explanation:

If Martin won first place in the 100-meter dash with a time of 14 23/100 seconds and samuel came in second place with a time of 15 7/10seconds, then Samuel beats Martin by (15 7/10-14 23/100)seconds

15 7/10 - 14 23/100

= 157/10-1423/100

= (1570-1423)/100

= 147/100

= 1.47seconds

This mean that Martin beats Samuel by 147humdreth of a second

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The sum of 27 and seven times a number is 125. Find the number.
zysi [14]
The number is 14

Here's the solution:

Let the number be x

According to the question,

27+7x=125

//Subtract 27 from both the sides

7x=125-27

7x=98

//divide both the sides by 7

x=98/7

x=14
9 0
3 years ago
Read 2 more answers
PLS HELP MEEEEE REEEEEEE
JulsSmile [24]

Answer:

$954.78

Step-by-step explanation:

Since it increases by 8.5%, all you have to do is multiply 879.98 by 1.085.

879.98 * 1.085 = $954.7783 = $954.78 (you always have to round to two decimal places with money)

5 0
3 years ago
A small junior college had an enrollment of 7,843 students in the year 1990 and 8,793 students in the year 2000. Let x=0 represe
abruzzese [7]

Correct answer is: (0,7843) and (10,8793)

Solution:-

Given that a junior college has an enrollment of 7843 students in 1990 and 8793 students in year 2000.

We have to write this data as (x,y) .

Where x= years after 1990 and y=number of students enrolled.

Since in 1990, 7843 students enrolled, x = 1990-1990=0

And y=7843.

Hence one ordered pair is (0,7843).

Let us find the years after 1990 for 2000 = 2000-1990 =10

Hence another ordered pair is (10,8793).

4 0
4 years ago
George is reading a book. At the end of 3 hours he has read 90 pages, and at the end of 5
jeka94

Answer:

74 pages/hour

Step-by-step explanation:

The average rate of change is the difference in the numbers of pages  divided by the difference in the numbers of hours.

At the end of 3 hours, 90 pages were read.

At he end of 5 hours, 238 pages were read.

Difference in hours: 5 hours - 3 hours = 2 hours.

Difference in pages: 238 pages - 90 pages = 148 pages

The average rate of change is the difference in pages divided by the difference in hours.

average rate of change = (148 pages)/(2 hours) = 74 pages/hour

5 0
3 years ago
A rectangle has length 127.3 cm and width 86.5 cm, both correct to 1 decimal place. Calculate the upperbound and the lowerbound
Mnenie [13.5K]

Answer:

Correct to 1dp

127.3 cm = 127.0 cm

86.5 cm = 87.0 cm

Upper limits:

127.0 cm = 127.05 cm

87.0 cm = 87.05 cm

Lower Limits:

127.0 cm = 126.95 cm

87.0 cm = 86.95 cm

upper limit of perimeter of rectangle:

P = 2(l+w)

= 2(127.05 + 87.05)

= 2(214.1)

= 428.2 cm

lower limit of perimeter of rectangle:

P = 2(l+w)

= 2(126.95 + 86.95)

= 2(213.9)

= 427.8 cm

therefore;

427.8 cm \leqslant perimeter < 428.2cm

8 0
3 years ago
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