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Anestetic [448]
3 years ago
7

Martin won first place in the 100-meter dash with a time of 14 23/100 seconds.Samuel came in second place with a time of 15 7/10

seconds. By how many hundredths of a second did martin beat Samuel?
Mathematics
2 answers:
ohaa [14]3 years ago
8 0

Answer: The answer is 47th of 100 of a second.


Step-by-step explanation:  Given that in the 100-metre dash, Martin won first place by taking a time of

M_t=14\dfrac{23}{100}=\dfrac{1423}{100}~\textup{seconds}.

And, Samuel came second by taking time of

S_t=15\dfrac{7}{10}=\dfrac{157}{10}~\textup{seconds}.

The difference between the time of arrival of Martin and Samuel is given by

t=S_t-M_t=\dfrac{157}{100}-\dfrac{1423}{100}=\dfrac{47}{100}.

Thus, Martin beat Samuel by forty seven - hundredth of a second.



nasty-shy [4]3 years ago
4 0

Answer:

Martin meats Samuel by 147humdreth of a second

Step-by-step explanation:

If Martin won first place in the 100-meter dash with a time of 14 23/100 seconds and samuel came in second place with a time of 15 7/10seconds, then Samuel beats Martin by (15 7/10-14 23/100)seconds

15 7/10 - 14 23/100

= 157/10-1423/100

= (1570-1423)/100

= 147/100

= 1.47seconds

This mean that Martin beats Samuel by 147humdreth of a second

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coldgirl [10]

\large{\underline{\underline{\pmb{\sf {\color {blue}{Solution:}}}}}}

Given,

Area = 225 yd²

Base = 30 yd

Height = [To be calculated]

To find:

The height of the given triangle.

We know that, area of a triangle is:

\frac{1}{2}  \times (b \times h) \\  \\  \leadsto \frac{1}{2} \times (30 \times h) \\  \\  \leadsto \frac{1}{2}   \times 30h \\  \\  \leadsto  \frac{1}{ \cancel{2}} \times  \cancel{30}h \\  \\  \leadsto1 \times 15h \\  \\  \leadsto \: h = 15 \: yd

Therefore, the require height is 15 yd.

\green\starProof:

\frac{1}{2}  \times (b \times h) \\  \\  \leadsto \frac{1}{2}  \times (30 \times 15) \\  \\  \leadsto \frac{1}{ \cancel{2}}   \times  \cancel{450} \\  \\  \leadsto1 \times 225  \\  \\  area = 225  {yd}^{2}

\boxed{ \frak \red{brainlysamurai}}

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