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Afina-wow [57]
3 years ago
12

The vertices of a right triangle are (-3,5), (4,-1) and (4,y) what is the value of y

Mathematics
1 answer:
alexgriva [62]3 years ago
4 0
Look in the attachment below.

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Kaelyn Kaitlyn start with $15 and saved $3.50 each day what expression represents the total amount of Taylor save
Vinil7 [7]

Your equation should look like this:

d = day

15 + 3.50d

Hope this helps!

6 0
3 years ago
The temperature in Alaska can reach -30 degrees Fahrenheit during the winter months it is colder in Antarctica than in the Alask
Fofino [41]

Answer:

B. -40°F

Step-by-step explanation:

its- clearly lower than -30

4 0
3 years ago
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The difference between the MDC and the LDC's​
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Answer: MDCs have advanced socially and economically, whereas LDCs are in the early stages of development.

8 0
2 years ago
PLEASE HELP URGENT<br><br> Given \tan \theta =0.6, find the value of b.
xxTIMURxx [149]

Answer:

b=8.5cm

Step-by-step explanation:

tanx (this represents tan theta, it's just easier to type) is equal to 0.6 and since the tanx ratio is opp/adj, we know that opp/adj = 0.6

To find what b is (adjacent as it is adjacent to the angle being used and it is not the hypotenuse), we just have to rearrange.

0.6=5.1/adj

to solve for adj, we can switch 0.6 and adj. (This works because to get adj by itself on one side you would multiply it to the other side and then divide 0.6 from both sides --> simple algebra)

so then you have

adj=5.1/0.6

adj=8.5cm

(if you want to check your solution you can use pythagoeran theorem, a^2+b^2=c^2) and sub everything in and make sure all the numbers equal the right thing!

6 0
2 years ago
A taxi ride costs p40.00 for the first 500 meters and each additional 300 meters or a fraction there of adds p3.50 to the fare.u
Zarrin [17]

The function which represents the taxi fare in terms of distance d in meter is f(d) = 3.50 ×\frac{d-500}{300} + 40 .

According to the question,

For first 500 meters cost is  40.00 and For each additional 300 meters cost is 3.50 .

Let, the total distance of taxi ride = d meters

Now, representing the equation of taxi fare in terms of distance when distance is less than 500

taxi fare = 3.50 ×  \frac{d-500}{300}  + 40

∴  f(d) = 3.50 ×  \frac{d-500}{300} + 40

To know more about functions refer below link: brainly.com/question/12431044

#SPJ4

8 0
2 years ago
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