Starting from what I know (the difference between ribbons), I decided to go from the bottom and work my way up. I then noticed a pattern (each sum was three more of the previous one), and decided to keep my pattern of the three numbers but not have to do any major mental work and instead add three to the previous sum until I got to 38.
Answer:
D.
Step-by-step explanation:
Find the average rate of change of each given function over the interval [-2, 2]]:
✔️ Average rate of change of m(x) over [-2, 2]:
Average rate of change = 
Where,
a = -2, m(a) = -12
b = 2, m(b) = 4
Plug in the values into the equation
Average rate of change = 
= 
Average rate of change = 4
✔️ Average rate of change of n(x) over [-2, 2]:
Average rate of change = 
Where,
a = -2, n(a) = -6
b = 2, n(b) = 6
Plug in the values into the equation
Average rate of change = 
= 
Average rate of change = 3
✔️ Average rate of change of q(x) over [-2, 2]:
Average rate of change = 
Where,
a = -2, q(a) = -4
b = 2, q(b) = -12
Plug in the values into the equation
Average rate of change = 
= 
Average rate of change = -2
✔️ Average rate of change of p(x) over [-2, 2]:
Average rate of change = 
Where,
a = -2, p(a) = 12
b = 2, p(b) = -4
Plug in the values into the equation
Average rate of change = 
= 
Average rate of change = -4
The answer is D. Only p(x) has an average rate of change of -4 over [-2, 2]
Answer:
3.4 x 107
Step-by-step explanation:
Answer:
Step-by-step explanation:
Given that a parking lot has two entrances. Cars arrive at entrance I according to a Poisson distribution at an average of 3 per hour and at entrance II according to a Poisson distribution at an average of 2 per hour.
Assuming the number of cars arriving at the two parking lots are independent we have total number of cars arriving X is Poisson with parameter 3+2 = 5
X is Poisson with mean = 5
the probability that a total of 3 cars will arrive at the parking lot in a given hour
= P(X=3) = 0.1404
b) the probability that less than 3 cars will arrive at the parking lot in a given hour
= P(X<3)
= P(0)+P(1)+P(2)
= 0.1247
A = 1/2aP
P = number of sides x length of each side
P = 8 x 5.8
P = 46.4
A= 1/2 x 7 x 46.4
A = 162.4