Answer:
height = 20.5068 m
Step-by-step explanation:
Given the data in the question;
First, lets calculate the amplitude, midline and period of 8minutes
Amplitude = 35 / 2 = 17.5
|A| = 17.5
A = - 17.5 { since the wheel starts at 6 o clock }
midline C = (35/2) + 3
C = 17.5 + 3
C = 20.5
And period is 8 minutes
⇒ 2π/B = 8
8B = 2π
B = 2π/8 = π/4
So our equation will be in the form of;
y = h(t) = Acos(B×t) + C
∴ h(t) = -17.5cos( π/4×t) + 20.5
Now, How high are you off the ground after 6 minutes
⇒ height = -17.5cos( π/4 × 6) + 20.5
height = -17.5cos( π/4 × 6) + 20.5
height = -17.5cos( 4.71238898) + 20.5
height = -17.5 × cos( 4.712) + 20.5
height = -17.5 × -0.00038898 + 20.5
height = 0.0068 + 20.5
height = 20.5068 m
Answer:
Height of the box = 11.5 in
Step-by-step explanation:
Let h be the height of the box.
Assuming the volume of the Box is
.
Given:
Length = Height - 4 = h - 4
Width = 3 in
We need to find the height of the box.
Solution:
We know that the volume of the box.

Substitute all given value in above formula.

Rewrite the equation as:



whole equation divided by 3.

Use quadratic formula with

Put these a, b and c value in above equation.




For positive sign
h = 11.5 in
For negative sign

h = -7.5
We take positive value of h.
Therefore, the height of the box h = 11.5 in
Create an equation: x*(x-3)=14
5.53112887 and 2.53112887
You can round the numbers and get 5.53 and 2.53
Answer:
{x | x ≤ -20}
Step-by-step explanation:
x + 17 ≤ -3
Subtract 17 from each side
x + 17-17 ≤ -3-17
x ≤ -20