Represent these consecutive numbers (assuming that they are all integers):
x
x+1
x+2
x+3
x+4
x+5
and so on
x+8
x+9 is the tenth number. x+9 = 10, so x = 9.
Think of it this way: there are 10 consecutive numbers, and the last one is 10.
Working backwards, we get the sequence 10, 9, ... 3, 2, 1.
The sum of such an arith sequence is equal to the count of the numbers times the average of the first and last terms:
sum here = 10(1+10)/2 = 5(11) = 55 (answer)
Hi!
<u>Given these two equations:</u>


We want to solve using the substitution method. Knowing that x is equal to y + 8, we can simply plug in 'y + 8' in for x in the second equation, like so:

Combine like terms on both sides:

Subtract y from both sides:

Subtract 8 from both sides:

Now, we can simply plug the y value in to the first equation, and solve for x:

Simplify:

<h3>
Therefore, x is equal to 12 and y is equal to 4.</h3>
<u>Learn more about the substitution (and also elimination!) method here:</u>
brainly.com/question/14619835
Answer: $5.54
Step-by-step explanation: 63 divided by 100 is 0.63, 0.63 x 8.8 is 5.544 and 5.544 rounded to the nearest cent is $5.54
No, both of the numbers are less than one whole and when you multiply them (I got 4/5) 4/5 is less than both of the factors.
5:3 x 6:2 can also be written as a fraction
5/3 x 6/2
Multiply across
30/6
Simplify
5/1
Rewrite
5:1 is your answer, or if your teacher does not want it simplified, 30:6
Hope I helped! :)