Answer:
19.51% probability that none of them voted in the last election
Step-by-step explanation:
For each American, there are only two possible outcomes. Either they voted in the previous national election, or they did not. The probability of an American voting in the previous election is independent of other Americans. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
In which 
is the number of different combinations of x objects from a set of n elements, given by the following formula.
And p is the probability of X happening.
42% of Americans voted in the previous national election.
This means that 
Three Americans are randomly selected
This means that 
What is the probability that none of them voted in the last election
This is P(X = 0).
19.51% probability that none of them voted in the last election
Answer:
f(3) = g(3)
General Formulas and Concepts:
<u>Algebra I</u>
- Reading a Coordinate Graph
- Coordinates (x, y)
- Solving systems of equations by graphing
- Functions
- Function Notation
Step-by-step explanation:
According to the graph, we see that both lines intersect at <em>x</em> = 3. Therefore, that means both lines at that <em>x</em> point will have the same <em>y</em> value. Both f(3) and g(3) would equal 6, leading us to the answer of f(3) = g(3).
N= 00
NNE= 022.5
NE= 045
ENE= 067.5
E= 090
ESE=112.5
SE= 135
SSE= 157.5
S=180
SSW= 202.5
SW= 225
WSW= 247.5
W=270
WNW= 292.5
NW= 315
NNW= 337.5
Hope i helped!
Answer: The average rate of change of Jack's investment from the third year to the fifth year is $6.43
Step-by-step explanation:
The function that defines the value of his investment after x years,
Putting the value of x as 3 and 5, we can get the value of his investment after 3 years and 5 years respectively.
Answer:
a2 – b2 = (a – b)(a + b)
(a + b)2 = a2 + 2ab + b2
a2 + b2 = (a + b)2 – 2ab
(a – b)2 = a2 – 2ab + b2
(a + b + c)2 = a2 + b2 + c2 + 2ab + 2bc + 2ca
(a – b – c)2 = a2 + b2 + c2 – 2ab + 2bc – 2ca
(a + b)3 = a3 + 3a2b + 3ab2 + b3 ; (a + b)3 = a3 + b3 + 3ab(a + b)
(a – b)3 = a3 – 3a2b + 3ab2 – b3 = a3 – b3 – 3ab(a – b)
a3 – b3 = (a – b)(a2 + ab + b2)
a3 + b3 = (a + b)(a2 – ab + b2)
(a + b)4 = a4 + 4a3b + 6a2b2 + 4ab3 + b4
(a – b)4 = a4 – 4a3b + 6a2b2 – 4ab3 + b4
a4 – b4 = (a – b)(a + b)(a2 + b2)
a5 – b5 = (a – b)(a4 + a3b + a2b2 + ab3 + b4
