The distance (d) between two points (x1,y1) and (x2,y2) is given by the formula
d = √ ((X2-X1)2+(Y2-Y1)2)
d = √ (-400--800)2+(300-200)2
d = √ ((400)2+(100)2)
d = √ (160000+10000)
d = √ 170000
The distance between the points is 412.310562561766
The midpoint of two points is given by the formula
Midpoint= ((X1+X2)/2,(Y1+Y2)/2)
Find the x value of the midpoint
Xm=(X1+X2)/2
Xm=(-800+-400)/2=-600
Find the Y value of the midpoint
Ym=(Y1+Y2)/2
Ym=(200+300)/2=250
The midpoint is: (-600,250)
Graphing the two points, midpoint and distance
P1 (-800,200)
P2 (-400,300)
Midpoint (-600,250)
The length of the black line is the distance between the points (412.310562561766)
Y=50+.05x
Just plug in the number of texts for x
y=50+.05(25)
y=51.25
^That was for 25 texts
Now just plug in all the other texts and replace that with x
Hope this helps!
The points at which a quadratic equation intersects the x-axis are referred to as x intercepts or zeros or roots of quadratic equation
Given :
The points at which a quadratic equation intersects the x-axis
The points at which the any quadratic equation crosses or touches the x axis are called as x intercepts.
At x intercepts the value of y is 0.
So , the points at which a quadratic equation intersects the x-axis is also called as zeros or roots of the quadratic equation .
The points at which a quadratic equation intersects the x-axis are referred to as x intercepts or zeros or roots of quadratic equation
Learn more : brainly.com/question/9055752
Answer:
The inequality is equivalent to x(x+2)(x−3)>0 , with the additional conditions that x≠0 and x≠3 .
Since x(x+2)(x−3) only changes signs when crossing −2 , 0 and 3 , from the fact that the evaluating the polynomial at 4 yields 24 , we see that the polynomial is
positive over (3,∞)
negative over (0,3)
positive over (−2,0)
negative over (−∞,−2)
Thus the solution set for your inequality is (−2,0)∪(3,∞) .
Step-by-step explanation:
hi Rakesh here is your answer :)
#shadow
Answer:
5
Step-by-step explanation:
Whenever you multiply square roots that have the same number inside the radicand, you get the number under the radicand. For example, the square root of 4 squared will equal four. Similarly, you are simply squaring the square root of 5, so you should get 5 as your answer.
