Provide an example of a function that does not have an inverse function. How do you prove that it is not a function?

Mathematics

1 answer:

SOVA2 [1]2 years ago

6 0

Answer:

f(x) = x^2 is a classic example

f( 3 ) = 9 and

f( -3 ) = 9, but

f^(-1)[9] is undefined because the result can be 3 and -3

You might be interested in

Using the technique in the model above, find the missing sides in this 30°-60°-90° right triangle.

nydimaria [60]

For this case what you should do is use the following trigonometric relationship:
tan (x) = C.O / C.A
Where
x: angle
C.O: opposite leg
C.A: adjoining catheto
Substituting the values we have:
tan (60) = long / short
tan (60) = long / 2
long = 2 * tan (60)
long = 3.46
Answer:
long = 3.46

4 0

3 years ago

Read 2 more answers

Use the Fundamental Theorem of Calculus to find the area of the region between the graph of the function x5 + 8x4 + 2x2 + 5x + 1

belka [17]

Answer:

The area of the region between the graph of the given function and the x-axis = 25,351 units²

Step-by-step explanation:

Given x⁵ + 8 x⁴ + 2 x² + 5 x + 15

If 'f' is a continuous on [a ,b] then the function

$F(x) = \int\limits^a_b {f(x)} \, dx$

By using integration formula

$\int{x^n} \, dx = \frac{x^{n+1} }{n+1} +c$

Given x⁵ + 8 x⁴ + 2 x² + 5 x + 15 in the interval [-6,6]

$\int\limits^6_^-6} (x^{5} + 8 x^{4} + 2 x^{2} + 5 x + 15) )dx$

On integration , we get

= $(\frac{x^{6} }{6} + \frac{8 x^{5} }{5} + 2 \frac{x^{3} }{3} +\frac{5 x^{2} }{2} + 15 x)^{6} _{-6}$

$F(x) = \int\limits^a_b {f(x)} \, dx = F(b) -F(a)$

= $(\frac{6^{6} }{6} + \frac{8 6^{5} }{5} + 2 \frac{6^{3} }{3} +\frac{5 6^{2} }{2} + 15X 6) - ((\frac{(-6)^{6} }{6} + \frac{8 (-6)^{5} }{5} + 2 \frac{(-6)^{3} }{3} +\frac{5 (-6)^{2} }{2} + 15 (-6))$