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3 years ago

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Four-ninths of those who rode the giant's gyro at the fair were delirious. All the rest were dazed. What fraction of those who r

ode the giant gyro was dazed

1 answer:

Paraphin [41]3 years ago

8 0

Answer:

5/9's of those who rode the giant gyro were dazed

Step-by-step explanation:

if 4/9's were delirious then the other 5/9's were dazed

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4) A salesperson is paid $60 per week plus $4.50 per sale. This week, the salesperson wants to earn at least $250. How many sale

sasho [114]

｡☆✼★ ━━━━━━━━━━━━━━ ☾

Subtract the $60 out of the total first

250 - 60 = 190

Divide this value by pay per sale:

190 / 4.50 = 42.2222

Thus, they must make 43 sales in order to meet the goal

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3 0

3 years ago

Indicate which property is illustrated in Step 5.

pychu [463]

Answer:

D)

Step-by-step explanation:

4 0

3 years ago

The scheduled arrival time for a daily flight from Boston to New York is 9:35 am. Historical data show that the arrival time fol

Lady_Fox [76]

Answer:

The mean is 11.5 minutes and the standard deviation is of 6.64 minutes

Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The mean is:

$M = \frac{a+b}{2}$

The standard deviation is:

$S = \sqrt{\frac{(b-a)^{2}}{12}}$

Arrival time of 9:18 am and a late arrival time of 9:41 am.

9:41 is 23 minutes from 9:18. So the time is uniformily distributed between 0 and 23 minutes, so a = 0, b = 23.

Mean:

$M = \frac{a+b}{2} = \frac{0+23}{2} = 11.5$

Standard deviation:

$S = \sqrt{\frac{(b-a)^{2}}{12}} = \sqrt{\frac{(23 - 0)^{2}}{12}} = 6.64$

The mean is 11.5 minutes and the standard deviation is of 6.64 minutes

8 0

2 years ago

Solve x^2 – 7x = -13.

lara31 [8.8K]

Answer:

No solutions I think

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

Suppose the average math SAT score for students enrolled at local community college is 490.4 with a standard deviation of 63.7.

lakkis [162]

Answer:

Option B) 9.1

Step-by-step explanation:

We are given the following in the question:

Average score = 490.4

Standard deviation = 63.7

Sample size, n = 49

Formula:

$=\dfrac{\sigma}{\sqrt{n}}$

Putting values, we get,

Standard error =

$=\dfrac{\sigma}{\sqrt{n}} = \dfrac{63.7}{\sqrt{49}} = 9.1$

Thus, the correct answer is

Option B) 9.1

8 0

2 years ago