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jek_recluse [69]
3 years ago
12

Question 2 (4 points)

Mathematics
2 answers:
dalvyx [7]3 years ago
4 0

Answer:

B

Step-by-step explanation:

got right on test

madreJ [45]3 years ago
3 0
I believe the correct answer is B
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X - y = 8 and -x + y = 4 solve the equation of linear equations by substitution​
ch4aika [34]

Answer:

No solution

Step-by-step explanation:

7 0
3 years ago
Relations expressed as ordered pairs are?
romanna [79]
The relations are domain and range
5 0
3 years ago
A coordinate system, or ____________________, is used to locate points in a 2-dimensional plane.
andreev551 [17]

Answer:

A coordinate system,or Coordinate plain ,is used to locate points in a 2-dimensional plane.

explanation:

A coordinate plain is formed by the intersection of two lines.One line is vertical and the other is horizontal.The vertical line is called y- axis and the horizontal line is called x-axis. It is two dimensional plane,which means it has length and breadth but no depth.The point where both the lines intersect is called the point of origin.Any point can be located on the coordinate plain by numbers(x,y). These pair of numbers are called coordinates.

It is used to plot points and lines.This system explains algebraic concepts .it has four equal divisions called quadrants namely I ,II,III,IV.

6 0
3 years ago
Given the matrices: 1 2 A= 1 -1 2 1 1 B= 3 4 Calculate AB: C11 C12 [2.1] х 1 2 3 4 C21 C22 C11 = C12 = -2 C22 - C215 DONE​
eduard

Answer:

\:c_{11}=-2,\:\:\:c_{12}=-2

\:c_{21}=5,\:\:\:c_{22}=8

Step-by-step explanation:

Given the matrices

A=\begin{pmatrix}1&-1\\ 2&1\end{pmatrix}

B=\begin{pmatrix}1&2\\ \:3&4\end{pmatrix}

Calculating AB:

\begin{pmatrix}1&-1\\ \:\:2&1\end{pmatrix}\times \:\begin{pmatrix}1&2\\ \:\:3&4\end{pmatrix}=\begin{pmatrix}c_{11}&c_{12}\\ \:\:\:c_{21}&c_{22}\end{pmatrix}

Multiply the rows of the first matrix by the columns of the second matrix

                                   =\begin{pmatrix}1\cdot \:1+\left(-1\right)\cdot \:3&1\cdot \:2+\left(-1\right)\cdot \:4\\ 2\cdot \:1+1\cdot \:3&2\cdot \:2+1\cdot \:4\end{pmatrix}

                                   =\begin{pmatrix}-2&-2\\ 5&8\end{pmatrix}

Hence,

\begin{pmatrix}c_{11}&c_{12}\\ \:\:\:c_{21}&c_{22}\end{pmatrix}=\begin{pmatrix}-2&-2\\ \:5&8\end{pmatrix}

Therefore,

\:c_{11}=-2,\:\:\:c_{12}=-2

\:c_{21}=5,\:\:\:c_{22}=8

5 0
3 years ago
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4 0
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