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8090 [49]
3 years ago
10

Is the relationship between 7s in 7,742 ant the 7s in 7,785 different in anyway? Explain

Mathematics
1 answer:
melisa1 [442]3 years ago
4 0
The relationship between the 7's is not different in any way because the sevens are all in the same place. The sevens are in the hundreds and thousands place.
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A rectangular carpet measures 12m by 5m. Part of the carpet is covered by a square rug of length 2m. What fraction of the carpet
guajiro [1.7K]

Answer:

¹/15

Step-by-step explanation:

Area of the rug = s²

Where s = 2 m

Area of the rug = 2² = 4 m²

Area of the rectangular carpet = length × width

Where,

Length = 12 m

Width = 5 m

Area = 12 × 5 = 60 m²

Fraction of the carpet covered by the rug = area of the rug ÷ area of the carpet = 4/60 = ¹/15

6 0
3 years ago
Please help!
agasfer [191]
Ok im not sure the answer yet so ima work on it at the same time while im explaining it. (The answer will probably be near the end)

We can use the elimination method to eliminate y out. To do that we multiply the first equation by 3.

6x+3y=-12

Now just subtract it from the other equation.

6x+3y=-12
5x+3y=-6

***x=-6***

Usually after doing the elimination method you will have to solve for x but in this case its already solved for you. If you want to find y now you just take the first equation and fill x with -6 and solve for y.

2(-6)+y=-4
-12+y=-4
y=8

Brainliest my answer if it helps you out?
4 0
3 years ago
Read 2 more answers
Since we don’t have math books to review can someone help with this and explain
vivado [14]

Answer:

Celsius is going up by 10's while Fahrenheit is going up by 18

Step-by-step explanation:

by subtracting the first two numbers then the next two you will see the pattern.

6 0
3 years ago
Let v1 =(-6,4) and v2=(-3,6) compute the following what i sthe angle between v1 and v2
Agata [3.3K]
\bf ~~~~~~~~~~~~\textit{angle between two vectors }
\\\\
cos(\theta)=\cfrac{\stackrel{\textit{dot product}}{u \cdot v}}{\stackrel{\textit{magnitude product}}{||u||~||v||}} \implies 
\measuredangle \theta = cos^{-1}\left(\cfrac{u \cdot v}{||u||~||v||}\right)\\\\
-------------------------------

\bf \begin{cases}
v1=\ \textless \ -6,4\ \textgreater \ \\
v2=\ \textless \ -3,6\ \textgreater \ \\
------------\\
v1\cdot v2=(-6\cdot -3)+(4\cdot 6)\\
\qquad \qquad 42\\
||v1||=\sqrt{(-6)^2+4^2}\\
\qquad \sqrt{52}\\
||v2||=\sqrt{(-3)^2+6^2}\\
\qquad \sqrt{45}
\end{cases}\implies \measuredangle \theta =cos^{-1}\left( \cfrac{42}{\sqrt{52}\cdot \sqrt{45}} \right)
\\\\\\
\measuredangle \theta =cos^{-1}\left(  \cfrac{42}{\sqrt{2340}} \right)\implies \measuredangle \theta \approx 29.74488129694^o
8 0
3 years ago
HELP I REALLY NEED HELP PLEASE :0 thanks
spayn [35]
The area of the triangle is 52.5 ft squared.
8 0
3 years ago
Read 2 more answers
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