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son4ous [18]
3 years ago
6

Use the distributive property to create an equivalent expression to 9x + 21.

Mathematics
1 answer:
vagabundo [1.1K]3 years ago
8 0
9x + 21 is the same as 3(3x +7)
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Find the distance between the points 3,7 and 15, 12 on the coordinate plane?
lana [24]
\text{Distance } = \sqrt{ (x_2 -x_1)^2 + (y_2 - y_1)^2}

\sqrt{ \left( 15 -  3\right)^2 +  \left( 12 -  7\right)^2}\\\\\sqrt{\left( 12\right)^2  + \left( 5\right)^2}\\\\\sqrt{    144  +   25 }\\\\\\ \sqrt{   169 } = \boxed{\bf{ 13}}
8 0
3 years ago
Angle ACB is an inscribed angle of circle P. What is the measure of angle ACB if arc MAB is equal to 50 degrees?
Yakvenalex [24]

∠ACB is an inscribed angle, so

m∠ACB= (1/2)mAB =(1/2)*50=25⁰

m∠ACB= 25⁰

3 0
3 years ago
Read 2 more answers
What is -2.6c - 2.8c equal??
Zina [86]

Answer:

-5.4c

Step-by-step explanation:

We're combining two "like" terms here.

It may make the problem easier to visualize if we write one of these terms over the other, as follows:

-2.6c

- 2.8c

----------

Adding, we get:

-2.6c

- 2.8c

----------

- 5.4c (answer)

3 0
3 years ago
A businessman was comparing his company's profits for two consecutive months. In November, n, were 0.04 thousand dollars more th
Firdavs [7]
N and d are both numbers of thousands of dollars.
Thus, if n = 1, that means $1000.

Here n = d + 0.4.
Note that in C, n+0.04=n is completely wrong.
Similarly, in D, d = 0.04 = n is completely wrong.
The "combined profit amount" for Nov. and Dec. is n + d = 3.15.

Only A matches this info.  Your answer is A.
5 0
3 years ago
K is the midpoint of PQ, P has
Pachacha [2.7K]

Answer:

Coordinates of Q (x_2,y_2) \:are\: \mathbf{(7,16)}

Option D is correct option.

Step-by-step explanation:

We are given:

K is the midpoint of PQ

Coordinates of P = (-9,-4)

Coordinates of K = (-1,6)

We need to find coordinates of Q  (x_2,y_2)

We will use the formula of midpoint: Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})

We are given midpoint K and x_1,y_1 the coordinates of P we need to find x_2,y_2 the coordinates of Q.

Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})\\(-1,6)=(\frac{-9+x_2}{2},\frac{-4+y_2}{2})\\

Now, we can write

-1=\frac{-9+x_2}{2}, 6=\frac{-4+y_2}{2}\\Simplifying:\\-2=-9+x_2\:,\: 12=-4+y_2\\-2+9=x_2\:,\: 12+4=+y_2\\x_2=7\:,\:y_2=16

So, we get coordinates of Q (x_2,y_2) \:are\: \mathbf{(7,16)}

Option D is correct option.

6 0
3 years ago
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