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2 years ago

How do o solve this equation? 4(3x - 10) + 7 = 15

Mathematics

2 answers:

Rama09 [41]2 years ago

5 0

X=4 because first u distruste and add the numbers then add 33 to both side

Aleksandr-060686 [28]2 years ago

4 0

Answer:

x = 4

Step-by-step explanation:

4(3x - 10) + 7 = 15

multiply 3x and 10 by 4

12x - 40 + 7 = 15

add 40 both sides

12x + 7 = 55

subtract 7 from both sides

12x = 48

divide

x = 4

hope this helps :)

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saveliy_v [14]

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3 years ago

Find the value of x if 196^×=14

castortr0y [4]

Answer:

x = $\frac{1}{2}$

Step-by-step explanation:

Note that $\sqrt{196}$ = 14

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7 0

3 years ago

What values of a and b make the equation true? StartRoot 648 EndRoot = StartRoot 2 Superscript a Baseline times 3 Superscript b

kramer

Option C: $a=3, b=4$ is the value of a and b

Explanation:

Given that the expression $\sqrt{648}=\sqrt{2^a\times3^b}$

We need to determine the value of a and b

Let us consider the term $\sqrt{648}$ and take the prime factorization of the term 648

Thus, we have,

648 divides by 2,

$648=2 \cdot 324$

324 divides by 2,

$648=2 \cdot 2 \cdot 162$

162 divides by 2,

$648=2 \cdot 2 \cdot 2 \cdot 81$

81 divides by 3,

$648=2 \cdot 2 \cdot 2 \cdot 3 \cdot 27$

27 divides by 3,

$648=2 \cdot 2 \cdot 2 \cdot 3 \cdot 3 \cdot 9$

9 divides by 3,

$648=2 \cdot 2 \cdot 2 \cdot 3 \cdot 3 \cdot 3 \cdot 3$

Thus, we have,

$\sqrt{648}=\sqrt{2^{3} \cdot 3^{4}}$

Therefore, equating the powers of 2 and 3, we get,

$a=3, b=4$

Hence, the value of a and b is 3 and 4

Thus, Option C is the correct answer.

4 0

3 years ago

Read 2 more answers

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Sever21 [200]

Answer:

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Step-by-step explanation:

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3 years ago

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alex41 [277]

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2 years ago