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3 years ago

Find the value of x. 10_3

Mathematics

1 answer:

Lisa [10]3 years ago

3 0

$67^o;\ 90^o\ and\ x^o\\angles\ on\ one\ side\ of\ a\ straight\ line\\will\ always\ add\ to\ 180^o.\\\\67^o+90^o+x^o=180^o\\157^o+x^o=180^o\ \ \ \ |subtract\ 157^o\ from\ both\ sides\\\boxed{x^o=23^o}$

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2 years ago

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2 years ago

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2 years ago

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Amiraneli [1.4K]

Answer:

$1\:\mathrm{year}$ (one solution)

Step-by-step explanation:

Let Ali's and Ahmet's ages be 3 and 4, respectively.

We have:

$\frac{3+x}{4+x}=\frac{4}{5}$

Solving for $x$ :

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3 years ago

16x² -9 = 4×² + (4x²+9)

lesya [120]

For this case we must solve the following equation:

$16x ^ 2-9 = 4x ^ 2 + (4x ^ 2 + 9)$

We remove the parentheses on the right side:

$16x ^ 2-9 = 4x ^ 2 + 4x ^ 2 + 9$

We add similar terms on the right side:

$16x ^ 2-9 = 8x ^ 2 + 9$

We subtract $8x ^ 2$ from both sides of the equation:

$16x ^ 2-8x ^ 2-9 = 9\\8x ^ 2-9 = 9$

We add 9 to both sides of the equation:

$8x ^ 2 = 9 + 9\\8x ^ 2 = 18$

We divide by 8 on both sides of the equation:

$x ^ 2 = \frac {18} {8}\\x ^ 2 = \frac {9} {4}$

We apply square root to both sides of the equation:

$x = \pm \sqrt {\frac {9} {4}}$

We have two roots:

$x_ {1} = \frac {3} {2}\\x_ {2} = - \frac {3} {2}$

Answer:

$x_ {1} = \frac {3} {2}\\x_ {2} = - \frac {3} {2}$

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3 years ago