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natka813 [3]
3 years ago
9

Solve for y 2(y+3)=18

Mathematics
1 answer:
jeka57 [31]3 years ago
3 0
Y= 6// 2(6+3)=18 because 6+ 3= 9 and 9x 2 = 18
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When asked to write a point slope equation for a line passing through the points (-4,-7) and (3,2) a student wrote y-2=-9/7(x-3)
AleksAgata [21]
First let's find the slope
Slope formula: 
\frac{y_2-y_1}{x_2-x_1} =slope
Given the two coordinates: 
(-4,-7) (3,2) 
 x1,y1  x2,y2

Plug these numbers into the formula
\frac{2-(-7)}{3-(-4)} = \frac{9}{7}
In this case the mistake that was made was that the student wrote the slope negative instead of positive
Final answer: 
<span>y-2=9/7(x-3)</span>
8 0
3 years ago
Complete the steps of the derivation of the quadratic formula step 1: (x+b/2a)^2-b^2-4ac/4a^2=0
CaHeK987 [17]
(x+b/2a)^2-(b^2-4ac)/2a=0
Step 2:
Re-write the expression:
(x+b/2a)^2=(b^2-4ac)/4a^2

Step 3:
get the square root of both sides:
x+b/2a=sqrt[(b^2-4ac)/4a^2]

Step 4:
Simplifying we get:
x+b/2a=sqrt[b^2-4ac]/2a

Step 5
Make x the subject:
x=-b/2a+/-sqrt[b^2-4ac]/2a


5 0
3 years ago
Read 2 more answers
Let X1 and X2 be independent random variables with mean μand variance σ².
My name is Ann [436]

Answer:

a) E(\hat \theta_1) =\frac{1}{2} [E(X_1) +E(X_2)]= \frac{1}{2} [\mu + \mu] = \mu

So then we conclude that \hat \theta_1 is an unbiased estimator of \mu

E(\hat \theta_2) =\frac{1}{4} [E(X_1) +3E(X_2)]= \frac{1}{4} [\mu + 3\mu] = \mu

So then we conclude that \hat \theta_2 is an unbiased estimator of \mu

b) Var(\hat \theta_1) =\frac{1}{4} [\sigma^2 + \sigma^2 ] =\frac{\sigma^2}{2}

Var(\hat \theta_2) =\frac{1}{16} [\sigma^2 + 9\sigma^2 ] =\frac{5\sigma^2}{8}

Step-by-step explanation:

For this case we know that we have two random variables:

X_1 , X_2 both with mean \mu = \mu and variance \sigma^2

And we define the following estimators:

\hat \theta_1 = \frac{X_1 + X_2}{2}

\hat \theta_2 = \frac{X_1 + 3X_2}{4}

Part a

In order to see if both estimators are unbiased we need to proof if the expected value of the estimators are equal to the real value of the parameter:

E(\hat \theta_i) = \mu , i = 1,2

So let's find the expected values for each estimator:

E(\hat \theta_1) = E(\frac{X_1 +X_2}{2})

Using properties of expected value we have this:

E(\hat \theta_1) =\frac{1}{2} [E(X_1) +E(X_2)]= \frac{1}{2} [\mu + \mu] = \mu

So then we conclude that \hat \theta_1 is an unbiased estimator of \mu

For the second estimator we have:

E(\hat \theta_2) = E(\frac{X_1 + 3X_2}{4})

Using properties of expected value we have this:

E(\hat \theta_2) =\frac{1}{4} [E(X_1) +3E(X_2)]= \frac{1}{4} [\mu + 3\mu] = \mu

So then we conclude that \hat \theta_2 is an unbiased estimator of \mu

Part b

For the variance we need to remember this property: If a is a constant and X a random variable then:

Var(aX) = a^2 Var(X)

For the first estimator we have:

Var(\hat \theta_1) = Var(\frac{X_1 +X_2}{2})

Var(\hat \theta_1) =\frac{1}{4} Var(X_1 +X_2)=\frac{1}{4} [Var(X_1) + Var(X_2) + 2 Cov (X_1 , X_2)]

Since both random variables are independent we know that Cov(X_1, X_2 ) = 0 so then we have:

Var(\hat \theta_1) =\frac{1}{4} [\sigma^2 + \sigma^2 ] =\frac{\sigma^2}{2}

For the second estimator we have:

Var(\hat \theta_2) = Var(\frac{X_1 +3X_2}{4})

Var(\hat \theta_2) =\frac{1}{16} Var(X_1 +3X_2)=\frac{1}{4} [Var(X_1) + Var(3X_2) + 2 Cov (X_1 , 3X_2)]

Since both random variables are independent we know that Cov(X_1, X_2 ) = 0 so then we have:

Var(\hat \theta_2) =\frac{1}{16} [\sigma^2 + 9\sigma^2 ] =\frac{5\sigma^2}{8}

7 0
3 years ago
What is 43x22 in ratio table?
serious [3.7K]

Answer:

A ratio table is a structured list of equivalent (equal value) ratios that helps us understand the relationship between the ratios and the numbers. Rates, like your heartbeat, are a special kind of ratio, where the two compared numbers have different units. Let's look at some examples of ratio table problems.

Step-by-step explanation:

7 0
2 years ago
The sum of two numbers is 25 one number is five less than the other number find the larger number
prohojiy [21]

*NOT MY WORK ITS FROM SOMEONE ELSE WHO ASKED THE SAME PROBLEM*

Answer: x=15, y= 10

Step-by-step explanation:

Answer: x=15, y=10

*Note: x and y are only variables used to solve this problem, but know that the two numbers are 15 and 10.

Step-by-step explanation:

For this problem, we can use system of equations. Let's use x for one number and y for the other.

First Equation:

x+y=25

We get this equation because it states that the sum of the two numbers is 25.

Second Equation:

y=x-5

We get this equation because it says one number (y) is 5 less than the other (x).

Since we have two equations, we can use substitution method to solve.

                                 [distribute 1 to (x-5)]

                                    [combine like terms]

                                        [add both sides by 5]

                                               [divide both sides by 2]

Now that we have x, we can plug it into any of the equations to find y.

                                         [plug in x=15]

                                        [subtract both sides by 15]

Finally, we have our answer, x=15 and y=10.

4 0
2 years ago
Read 2 more answers
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