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3 years ago

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ula1" title="( {8x}^{2} + 4x + 4) - (7x + 9)" alt="( {8x}^{2} + 4x + 4) - (7x + 9)" align="absmiddle" class="latex-formula">
solve

1 answer:

son4ous [18]3 years ago

4 0

Answer:

$8x^{2} -3x-5$

Step-by-step explanation:

$8x^{2} +4x+4-7x-9$

$8x^{2} +4x-7x+4-9$

$8x^{2} -3x-5$

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2 years ago

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3 years ago

$i^5+i^{-25}+i^{45}$<img src="https://tex.z-dn.net/?f=%24i%5E5%2Bi%5E%7B-25%7D%2Bi%5E%7B45%7D%24" id="TexFormula1" title="$i^5+i

gregori [183]

$i^5+i^{-25}+i^{45}$

Rewrite the term $i^{-25}$

$=i^5+\dfrac{1}{i^{25}}+i^{45}$

Expand each term so we have

$=i(i^2)^2+\dfrac{1}{i(i^2)^{12}}+i(i^2)^{22}$

Use the fact that $i^2=-1$

$=i(-1)^2+\dfrac{1}{i(-1)^{12}}+i(-1)^{22}$

Use the fact that $(-1)^{a}=1$ when a is an even number

$=i+\dfrac{1}{i}+i$

Simplify

$=i-i+i$

$=i$

Let me know if you need any clarifications, thanks!

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2 years ago

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