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1 year ago

Find the difference (2x+7)-6(5x-8)

Mathematics

2 answers:

Greeley [361]1 year ago

5 0

Answer:

-28x+55

Step-by-step explanation:

step 1. Substitute the -6 into the 5x-8.

(2x+7)-6(5x-8)

2x+7-30x+48

step 2. Combine like terms.

2x+7-30x+48

Now, these are the simple steps you can follow.

sveticcg [70]1 year ago

4 0

Answer:

-28x-41

Step-by-step explanation:

6*5x-6*8

30x-48

2x+7-30x-48 = 2x-30x+7-48 = -28x+7-48 = -28x+(-41)= -28x-41

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The football team plays at a stadium with

12345 [234]

Answer:

1,100

Step-by-step explanation:

6 0

2 years ago

Based on the graph below, what is the y-intercept?<br><br><br><br> -5<br> -3<br> 3<br> 5

Crank

The y-intercept is -3

7 0

2 years ago

Read 2 more answers

Can anyone help me I did it I'm just checking :)

lukranit [14]

Answer:

Step-by-step explanation:

2x + 5 = 3x - 7

5 + 7 = 3x - 2x

12 = x

8 0

2 years ago

What's the answer for this question? (The numbers after the letters are indexes btw) 27a9 x 18b5 x 4c2 Over 18a4 x 12b2 x 2c

zysi [14]

Answer:

$\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c} = \frac{9}{2}a^5b^3c$

Step-by-step explanation:

Given

$\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c}$

Required

Simplify

$\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c}$

Cancel out 18

$\frac{27a^9 * b^5 * 4c^2 }{a^4 * 12b^2 * 2c}$

Divide 4 and 2

$\frac{27a^9 * b^5 * 2c^2 }{a^4 * 12b^2 *c}$

Divide 27 and 12 by 3

$\frac{9a^9 * b^5 * 2c^2 }{a^4 * 4b^2 *c}$

Apply law of indices

$\frac{9a^{9-4} * b^{5-2} * 2c^{2-1} }{4}$

$\frac{9a^5 * b^3 * 2c }{4}$

Divide 2 and 4

$\frac{9a^5 * b^3 * c}{2}$

$\frac{9a^5b^3c}{2}$

Rewrite as:

$\frac{9}{2}a^5b^3c$

Hence:

$\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c} = \frac{9}{2}a^5b^3c$

4 0

2 years ago

0.5 recurring as a fraction

Klio2033 [76]

0.5 = 5/10 = 1/2

The answer is 1/2

5 0

2 years ago

Read 2 more answers