Answer:
I would say false
Explanation:
Threads can be add to anything there is no say in where you should add the thread and into what
Answer:
The answer to this question is "15 line".
Explanation:
A function is a block of ordered, portable code used to perform a single, connected operation. The syntax of function declaration can be given as:
Syntax :
returntype functionName(parameter1, parameter2); //function prototype
or declaration
returntype functionName(parameter1, parameter2) //function definition or header of the function
{
//function body.
//function implementation
//return value;
}
In the given question the header of the showDub function is on line 15.
That's why the answer to this question is "15 line".
Uhh i need points so i don’t fail math.
Answer:
D. a studio monitor
Explanation:
A studio monitor is an electrical equipment that is used to enhance the quality of sound or music. It work like a speaker that can be used professionals to record audio songs, to make films and some other applications with good quality. It is usually used in studios where producer must ensures that the quality of music. As in music industry the quality of music depends on the quality of instrument used for the purpose of recording.
<em>This is the reason that, Jimmy and his friends should choose a Studio Monitor to achieve the most accurate sound quality.</em>
The simulation, player 2 will always play according to the same strategy.
Method getPlayer2Move below is completed by assigning the correct value to result to be returned.
Explanation:
- You will write method getPlayer2Move, which returns the number of coins that player 2 will spend in a given round of the game. In the first round of the game, the parameter round has the value 1, in the second round of the game, it has the value 2, and so on.
#include <bits/stdc++.h>
using namespace std;
bool getplayer2move(int x, int y, int n)
{
int dp[n + 1];
dp[0] = false;
dp[1] = true;
for (int i = 2; i <= n; i++) {
if (i - 1 >= 0 and !dp[i - 1])
dp[i] = true;
else if (i - x >= 0 and !dp[i - x])
dp[i] = true;
else if (i - y >= 0 and !dp[i - y])
dp[i] = true;
else
dp[i] = false;
}
return dp[n];
}
int main()
{
int x = 3, y = 4, n = 5;
if (findWinner(x, y, n))
cout << 'A';
else
cout << 'B';
return 0;
}
