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igor_vitrenko [27]
3 years ago
11

Alina spent no more than $45 on gas for a road trip. The first gas station she used charged $3.50 per gallon and the second gas

station charged $4.00 per gallon. Which inequality relates the number of gallons of gas she bought at the first station, x, the number of gallons of gas she bought at the second station, y, and the total amount she paid? What are the possible values of y?
a. 3.5x + 4y ≥ 45, y ≥ 11.25
b. 3.5x + 4y ≥ 45, 0 ≤ y ≤ 10.375
c. 3.5x + 4y ≤ 45, 0 ≤ y ≤ 11.25
d. 3.5x + 4y ≤ 45, y ≥ 10.375
Mathematics
2 answers:
xenn [34]3 years ago
5 0
The answer is C.Your welcome
egoroff_w [7]3 years ago
5 0

Answer:

the solution to this problem would be c, i hope this helps

Step-by-step explanation:


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Write an equations in point-slope form for a horizontal line that passes through (-4, -1)
Flura [38]

Answer:

Y=-1; y+1=0(x+4)

Step-by-step explanation:

Point slope form: y-y1=m(x-x1)

A horizontal line has a slope of "0" therefore our "m" value is 0

So

y+1=0(x+4)

Y+1=0x+0

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Hope this helps!

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Answer:

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Step-by-step explanation:

The equation is in y=mx+b form

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So, for this line, y=-4x+10

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Assume the sample variances to be continuous measurements. Find the probability that a random sample of 25observations, from a n
konstantin123 [22]

Answer:

a) P(4S^2 > 4*9.1) = P(\chi^2_{24} >36.4) = 0.0502

b)P(13.848Step-by-step explanation:

Previous concepts

The Chi Square distribution is the distribution of the sum of squared standard normal deviates .

For this case we assume that the sample variance is given by S^2 and we select a random sample of size n from a normal population with a population variance \sigma^2. And we define the following statistic:

T = \frac{(n-1) S^2}{\sigma^2}

And the distribution for this statistic is T \sim \chi^2_{n-1}

For this case we know that n =25 and \sigma^2 = 6 so then our statistic would be given by:

\chi^2 = \frac{(n-1)S^2}{\sigma^2}=\frac{24 S^2}{6}= 4S^2

With 25-1 =24 degrees of freedom.

Solution to the problem

Part a

For this case we want this probability:

P(S^2 > 9.1)

And we can multiply the inequality by 4 on both sides and we got:

P(4S^2 > 4*9.1) = P(\chi^2_{24} >36.4) = 0.0502

And we can use the following excel code to find it: "=1-CHISQ.DIST(36.4,24,TRUE)"

Part b

For this case we want this probability:

P(3.462 < S^2

If we multiply the inequality by 4 on all the terms we got:

P(3.462*4 < 4S^2 < 4*10.745)= P(13.848< \chi^2And we can find this probability like this:P(13.848And we use the following code to find the answer in excel: "=CHISQ.DIST(42.98,24,TRUE)-CHISQ.DIST(13.848,24,TRUE)"

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