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kiruha [24]
3 years ago
15

Find the slope and the y-intercept of the line in the graph.​

Mathematics
2 answers:
Radda [10]3 years ago
8 0

The slope is 2. The y-intercept is 4.

Explanation:

The line constantly goes up to units for every unit that it goes to the right. The y intercept is 4 because it is 4 on the y-axis when x is 0.

asambeis [7]3 years ago
5 0

9514 1404 393

Answer:

  • slope: 2
  • y-intercept: 4

Step-by-step explanation:

The y-intercept is where the line crosses the y-axis. This graph has a y-intercept of 4. The point coordinates there are (0, 4).

__

The slope is the ratio of rise to run. It is convenient to identify places where the graph crosses grid intersections. This graph has a rise of 2 units for a run of 1. So, the slope is 2/1 = 2.

The slope is 2; the y-intercept is 4.

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In a certain assembly plant, three machines B1, B2, and B3, make 30%, 20%, and 50%, respectively. It is known from past experien
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Answer:

The probability that a randomly selected non-defective product is produced by machine B1 is 11.38%.

Step-by-step explanation:

Using Bayes' Theorem

P(A|B) = \frac{P(B|A)P(A)}{P(B)} = \frac{P(B|A)P(A)}{P(B|A)P(A) + P(B|a)P(a)}

where

P(B|A) is probability of event B given event A

P(B|a) is probability of event B not given event A  

and P(A), P(B), and P(a) are the probabilities of events A,B, and event A not happening respectively.

For this problem,

Let P(B1) = Probability of machine B1 = 0.3

P(B2) = Probability of machine B2 = 0.2

P(B3) = Probability of machine B3 = 0.5

Let P(D) = Probability of a defective product

P(N) = Probability of a Non-defective product

P(D|B1) be probability of a defective product produced by machine 1 = 0.3 x 0.01 = 0.003

P(D|B2) be probability of a defective product produced by machine 2 = 0.2 x 0.03 = 0.006

P(D|B3) be probability of a defective product produced by machine 3 = 0.5 x 0.02 = 0.010

Likewise,

P(N|B1) be probability of a non-defective product produced by machine 1 = 1 - P(D|B1) = 1 - 0.003 = 0.997

P(N|B2) be probability of a non-defective product produced by machine 2  = 1 - P(D|B2) = 1 - 0.006 = 0.994

P(N|B3) be probability of a non-defective product produced by machine 3 = 1 - P(D|B3) = 1 - 0.010 = 0.990

For the probability of a finished product produced by machine B1 given it's non-defective; represented by P(B1|N)

P(B1|N) =\frac{P(N|B1)P(B1)}{P(N|B1)P(B1) + P(N|B2)P(B2) + (P(N|B3)P(B3)} = \frac{(0.297)(0.3)}{(0.297)(0.3) + (0.994)(0.2) + (0.990)(0.5)} = 0.1138

Hence the probability that a non-defective product is produced by machine B1 is 11.38%.

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Answer:

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Step-by-step explanation:

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