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lozanna [386]
3 years ago
9

Verify the linear approximation at (0, 0) for

Mathematics
1 answer:
Softa [21]3 years ago
5 0
You need to plug in the (0,0) that’s it
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Monthly only? or more details
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3 years ago
Write the equation of a polynomial of degree 3, with zeros 1, 2 and -1 where f(0)=2
drek231 [11]

<u>Answer:</u>

The equation of a polynomial of degree 3, with zeros 1, 2 and -1 is x^{3}-2 x^{2}-x+2=0

<u>Solution:</u>

Given, the polynomial has degree 3 and roots as 1, 2, and -1. And f(0) = 2.

We have to find the equation of the above polynomial.

We know that, general equation of 3rd degree polynomial is  

F(x)=x^{3}-(a+b+c) x^{2}+(a b+b c+a c) x-a b c=0

where a, b, c are roots of the polynomial.

Here in our problem, a = 1, b = 2, c = -1.

Substitute the above values in f(x)

F(x)=x^{3}-(1+2+(-1)) x^{2}+(1 \times 2+2(-1)+1(-1)) x-1 \times 2 \times(-1)=0

\begin{array}{l}{\rightarrow x^{3}-(3-1) x^{2}+(2-2-1) x-(-2)=0} \\ {\rightarrow x^{3}-(2) x^{2}+(-1) x-(-2)=0} \\ {\rightarrow x^{3}-2 x^{2}-x+2=0}\end{array}

So, the equation is x^{3}-2 x^{2}-x+2=0

Let us put x = 0 in f(x) to check whether our answer is correct or not.

\mathrm{F}(0) \rightarrow 0^{3}-2(0)^{2}-0+2=2

Hence, the equation of the polynomial is x^{3}-2 x^{2}-x+2=0

3 0
3 years ago
2(x + 2) + 3x = 2(x + 1) + 1 como lo puedo resolver?​
Reptile [31]

Answer:

x=-1/3

Step-by-step explanation:

2(x+2)+3x=2(x+1)+1

2x+4+3x=2x+2+1

5x+4=2x+3

5x-2x+4=3

3x+4=3

3x=3-4

3x=-1

x=-1/3

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4 years ago
What is 9 + 10 wrong answers only
astra-53 [7]

Answer:

A car

Step-by-step explanation:

4 0
3 years ago
I will give many points and brainlest if you find the area of the polygon
charle [14.2K]

Answer:

28

Step-by-step explanation:

You can split the figure up

3*4/2 = 6

3*4/2 = 6

8*2 = 16

6+6+16 = 28

8 0
3 years ago
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