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Sveta_85 [38]
3 years ago
3

Triangle K M L is shown. Line L K extends through point J to form exterior angle J K M. Which angle is an adjacent interior angl

e to ∠JKM? ∠JKL ∠MKL ∠KLM ∠LMK

Mathematics
2 answers:
Nadya [2.5K]3 years ago
6 0

Answer:

The correct option is;

∠MKL

Step-by-step explanation:

From the construction of the line LKJ to form the exterior  angle ∠JKM, we have that the segment MK of triangle KML forms two adjacent angles on JKL which are ∠JKM and ∠MKL, therefore, the adjacent interior angle to angle ∠JKM is angle ∠MKL

PLease find attach The drawing of triangle KML showing the extended point J

S_A_V [24]3 years ago
5 0

Answer:

B) ∠MKL

Step-by-step explanation:

Took the quiz on edge

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Olegator [25]

Answer:

answer of 2a)

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He started with an account balance of -$6 and paid the debt off so his account balance is 0. If d is the amount money he deposited to pay off his debt, then

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answer of 2b)

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Is 3.4 x 10 ⁵ a irrational number or rational number?
Luba_88 [7]

Answer:

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Step-by-step explanation:

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4 years ago
Given: ABCD ∥gram, BK ⊥ AD , AB ⊥ BD AB=6, AK=3 Find: m∠A, BK, Area of ABCD
Morgarella [4.7K]

1. Consider right triangle ABK. In this triangle AB is the hypotenuse, BK and AK are legs. By the Pythagorean theorem,

AB^2=AK^2+BK^2,\\\\6^2=3^2+BK^2,\\\\BK^2=36-9=27,\\\\BK=3\sqrt{3}\ un.

2. Use the definition of \cos \angle A:

\cos \angle A=\dfrac{\text{adjacent leg}}{\text{hypotenuse}}=\dfrac{AK}{AB}=\dfrac{3}{6}=\dfrac{1}{2}.

Then m\angle A=60^{\circ}.

3. Consider right triangle ABD. In this triangle AD is the hypotenuse, AB and BD are legs. Since  m\angle A=60^{\circ}, then

m\angle BDA=180^{\circ}-90^{\circ}-60^{\circ}=30^{\circ}.

The leg that is opposite to the angle of 30° is half of the hypotenuse, so

AD=2AB=12\ un.

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