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Naya [18.7K]
3 years ago
7

I need help I tried to do this question with one C and with two C

Mathematics
1 answer:
OverLord2011 [107]3 years ago
3 0

There are two c's. You must pay attention to capitalization, there's a lowercase c and an uppercase C which represent two different variables. Also, the W is capitalized which could make your answer incorrect if you don't use the same notation.

Solving for small c..

C = \frac{Wtc}{1,000}   \\\\ 1,000C = Wtc \\\\\frac{1,000C}{Wt}= c

So it's the answer shown in the picture, but it  should be a capital W instead of a lowercase w.  






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What are the zeros of f(x) = x2 - 12x + 36?
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Answer:

c. x = 6 only

Step-by-step explanation:

In order to calculate the zeros of f(x), we need to set it equal to zero and find the corresponding values of x.

x^{2}-12x+36=0

Using the midterm breaking, we can split -12x into two such terms whose sum will be -12x and product will be 36x². These two terms are -6x and -6x

So, the above expression can be written as:

x^2-6x-6x+36=0\\\\ x(x-6)-6(x-6)=0\\\\ (x-6)(x-6)=0\\\\ (x-6)^{2}=0\\\\ x-6=0\\\\ x=6

This means, the zero of f(x) occurs at x = 6 only.

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3 years ago
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Step-by-step explanation:

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PLEASE HELP!<br>I'm confused..<br><br>Solve each equation for y.<br>please show work
8090 [49]

Answer:

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Step-by-step explanation:

b. The particualar steps for solving a linear equation such as this may vary from one equation to another. In general, you want to put all the y-terms on one side of the equal sign and everything else on the other side. Here's how we'll do that in this case.

Use the distributive property to eliminate parentheses.

... 6x -3y +12 = 4x -3

Find the unwanted terms on the side of the equation where y is, then add their opposite. In this case, we're adding -(6x+12)

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Divide by the coefficient of y.

... y = -2x/(-3) -15/(-3)

... y = 2/3x +5

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c. This is a 2nd-degree (quadratic) equation with y as its only variable. The factor (2y+1) appears in both terms so we can use the distributive property to factor it out. Then the equation becomes ...

... (y +3)(2y +1) = 0

The zero product rule tells us this product will be zero only when one or the other of the factors is zero. This fact helps us find the values of y that are the solution to the equation.

For y+3 = 0:

... y + 3 = 0

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... 2y +1 = 0

... y +1/2 = 0 . . . . divide by 2

... y = -1/2 . . . . . . add -1/2

The solutions are y = -3 or y = -1/2.

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4 years ago
8(3x^5) - (2x)^3 (5x^2) simplify I need the work I got the first part down but the second im having trouble with
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You have to do 2 to the third power and then 5 to the second power then times them both to get your answer which is 200^5.



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