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Luba_88 [7]
4 years ago
13

50 points!!!!! PLS answer

Mathematics
2 answers:
maks197457 [2]4 years ago
5 0

Answer:

woop you'll have to ask the question

Step-by-step explanation:

Andreas93 [3]4 years ago
3 0

Answer:

where is the question??


Step-by-step explanation:


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A chemist has a solution of 50% pure acid and another solution of 80% pure acid. How many gallons of each will make 600 gallons
bonufazy [111]
Let x=amount of 50% solution and y=amount of 80% solution.
x+y=600 gallons; amount of pure acid in the mixture has to be 72% of 600=432 gallons.
So 0.5x+0.8y=432; but y=600-x so 0.5x+0.8(600-x)=432, 0.5x+480-0.8x=432.
480-432=0.3x, 48=0.3x so x=160 so y=600-160=440 gallons.
160 gallons of 50% and 440 gallons of 80%.
5 0
3 years ago
Read 2 more answers
Factor by grouping...
kupik [55]

Answer:

x^3+9x^2-6x-54=0

Step-by-step explanation:

or, x^2(x+9)-6(x+9)=0

or,(x+9)(x^2-6)=0

Either

x+9=0

x=-9

Or

x^2-6=0

x^2=6

x=-9,x^2 =6

7 0
4 years ago
How do you shift exponential functions?
dlinn [17]

Shift the graph of f(x)=bx f ( x ) = b x left c units if c is positive and right c units if c is negative. Shift the graph of f(x)=bx f ( x ) = b x up d units if d is positive and down d units if d is negative.

7 0
3 years ago
Read 2 more answers
How do you find the perimeter of a parallelogram​
poizon [28]
  • There may be a simpler way to solve this question, however if you are currently learning distance formula, then this may be the correct way to solve it.

Answer: D

Step-by-step explanation:<em>To find the perimeter of this parallelogram, you would have to find the distance between the coordinates. </em>

I would use the distance formula for this question.

Distance Formula - d=\sqrt{(x_2 -x_1)^{2}+(y_2 -y_1)^{2}}

Ok, let's find the length of side AB.

Coordinates of A = (-5, -7)  This will be our second x and y coordinates [x_2,y2]

Coordinates of B = (2, -3) These will be our first x and y coordinates   [x_1,y1]

Now Substitute Into The Equation -

d=\sqrt{(-5-2)^{2} +(-7-(-3))^{2} }

Solve/Simplify -

\sqrt{(-5-2)^2+(-7-(-3))^2} \\ \\ \sqrt{(-5-2)^2+(-7+3)^2} \\\\\sqrt{(-7)^2+(-4)^2}\\\\ \sqrt{49+16} \\\\ \sqrt{65}

  • <em>Great! We have the first distance for the perimeter.</em>

Now let's solve for side CB

Point C = (-1, 2) This will be our second x and y coordinates [x_2,y2]

Point B = (2, -3) These will be our first x and y coordinates   [x_1,y1]

Substitute and Solve -

\sqrt{(-1-2)^2+(2-(-3))^2}\\\\sqrt{(-1-2)^2+(2+3)^2}\\\\\ \sqrt{(-3)^2+(5)^2}\\\\ \sqrt{9+25}\\\\\sqrt{34}

  • <em>Now we have our second distance for the perimeter.</em>

Now solve for the other two sides -

Because this shape is a rectangle, the parallel lines are the same length.

Now, find the perimeter-

\sqrt{65}+ \sqrt{65}+ \sqrt{34} +\sqrt{34}

  • That equals about 27.79, rounding up to 27.8

<em>Hoped this helped!~</em>

6 0
3 years ago
Hi guys, do you know where i can get multi choice maths questions for year 9 ?? thanks guys
NikAS [45]
Uhh i think you could purchas of teachers pay teachers they have amazing worksheets
5 0
3 years ago
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