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marta [7]
3 years ago
5

What is the slope of the line containing the ordered pairs (5,-3) and (-2,-3)

Mathematics
1 answer:
Anni [7]3 years ago
3 0

Answer:

0

Step-by-step explanation:

Use the slope formula: m = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}

m = \frac{-3+3}{-2-5}=\frac{0}{-7} =0

The slope of the line is 0.

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Solve -1.2x+2.5=0.8x+6.5<br>x=2<br>O<br>x=-4 0​
Bond [772]

Answer:

x = - 2

Step-by-step explanation:

Given

- 1.2x + 2.5 = 0.8x + 6.5 ( subtract 0.8x from both sides )

- 2x + 2.5 = 6.5 ( subtract 2.5 from both sides )

- 2x = 4 ( divide both sides by - 2 )

x = - 2

4 0
3 years ago
How long is the Yangtze river
Nastasia [14]

Answer:

3,915 mi

Step-by-step explanation:

8 0
3 years ago
PLS HELP IT’S DUE TMR!!
ValentinkaMS [17]

Answer:

Use ≈ (approximately equal) sign as the scientific notation.

Step-by-step explanation:

(a) 0.001872 ≈ 0.0019

(b) 0.3411 ≈ 0.34

(c) 0.000845 ≈ 0.00085

*Zeros before non-zero numbers are not significant.

*Zeros appearing between two non-zero digits are significant.

Hope this helps!!

6 0
2 years ago
Find the 100th term in the arithmetic sequence 0,5,10,15
Viktor [21]

Answer:

easy peasy,

the 'n' th term of any arithmetic sequence can be found with the following formula

=> a + ( n-1) d, [where 'a' if the first term of the sequence, 'n' the number of term we need to find, and 'd' being the common difference between each two consecutive term of the sequence)

all in this case would be,

a = 0

n = 100

d = +5

hence the 100th term would be,

=>  0 + (100 - 1) 5

=> 99 x 5

=> 495

8 0
3 years ago
Hello can someone help me simplify 4) and 5)? Thank you and please include steps :)
Leni [432]
Alrighty

remember some rules
(ab)^c=(a^c)(b^c)
and
x^{-m}=\frac{1}{x^m}
and
x^0=1 for all real values of x
and
(a^b)^c=a^{bc}
and
(\frac{a}{b})^c=\frac{a^c}{b^c}
and
(a/b)/(c/d)=(ad)/(bc)
and
(a^b)(a^c)=a^{b+c}
and
\frac{a^m}{a^n}=a^{m-n}
and don't forget pemdas
example: -x^m=-1(x^m) but (-x)^m=(-1)^m(x^m)

so

4.
(\frac{c^{-2}}{2})^{-2}=

\frac{(c^{-2})^{-2}}{2^{-2}}=

\frac{c^4}{\frac{1}{2^2}}=

\frac{c^4}{\frac{1}{4}}=

4c^4



5.

\frac{(-a)^4bc^5}{-a^2b^{-3}c^0}=

\frac{(-1)^4(a)^4bc^5}{-1(a^2)(\frac{1}{b^3}(1)}=

\frac{(1)a^4bc^5}{\frac{(-1)(a^2)}{b^3}}=

\frac{(a^4bc^5)b^3}{(-1)(a^2)}=

\frac{-a^4b^4c^5}{a^2}=

-a^2b^4c^5
3 0
3 years ago
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