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WARRIOR [948]
3 years ago
7

You have 10 coins in a jar, 3 pennies, 5 quarters and two dimes. if you take out 3 quarters, 2 pennies and 2 dimes, how much cen

ts do you have left?
Mathematics
2 answers:
Maru [420]3 years ago
3 0
To do this i add them uo and easily subtract woth a hand held calculator
Agata [3.3K]3 years ago
3 0

You start with:  5 quarters, 3 pennies, 2 dimes
Remove:         3 Quarter   2 pennies   2 dimes
End with:       2 Quarters 1 penny    0 dimes

=51 cents. 
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Step-by-step explanation:

4 0
3 years ago
Please show me how to start this question but don't give me the answer
Natalija [7]

To make the input-output table, we need to plug in the given vaues of x's in the equation to get their corresponding values of y.

Let's plug in x = -2 in y = 6x +5. So,

y = 6( -2) + 5 = -12 + 5 = -7

Similarly for x = 0, y= 6(0) + 5 = 5

For x = 1, y = 6(1) + 5 = 6 + 5 = 11

For x = 4, y = 6(4) + 5 = 24 + 5 = 29

For x= 5, y = 6(5) + 5 = 30 + 5 = 35.

I am attaching the input -output table from the above result.

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4 0
3 years ago
Solve for x and y: 7y−5x=31 &amp; x=4−2y
horrorfan [7]
7*y - 5*(4-2y) = 7y - 20 +10y = 17y-20 = 31,

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Weird 20 min without answer!
7 0
3 years ago
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URGENT PLEASE!! I’ll give you brainliest! You just have to find x
maks197457 [2]

Step-by-step explanation:

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5 0
3 years ago
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