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melamori03 [73]

3 years ago

6

Vlad spent 20 minutes on his homework and then completely solved x math problems that took 2 minutes to complete. What is the eq

uation tat can be used to find the value of y, the total that Vlad spent on his homework, and what are the constraints on the values on the values of x and y

1 answer:

aalyn [17]3 years ago

5 0

Answer:

20 divided by 2 = 10

Step-by-step explanation:

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2/3(3/5x+9)=(2x+40)<br><br> Algebra II

Gennadij [26K]

Answer:

value if x is -21.25.

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8 0

2 years ago

Write the following probability as a percentage 3/5

cupoosta [38]

Hi there,

The percentage of 3/5 would be %60

3/5
3x20=60
5x20=100

Now you have 60/100, turn that into a percentage and you have %60.

4 0

3 years ago

Someone help factor. This for me

Ksenya-84 [330]

Answer:

w(4 - 11w)

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

Can please someone help me? The question is in the picture. Thank you

maxonik [38]

Answer:

C. $9\pi$

Step-by-step explanation:

We proceed to solve for $x$ by the Pythagorean Theorem:

$(x+1)^{2} = (x-1)^{2} + (2\cdot x - 4)^{2}$ (1)

$x^{2} + 2\cdot x + 1 = (x^{2}-2\cdot x + 1) + (4\cdot x^{2}-16\cdot x + 16)$

$x^{2} + 2\cdot x + 1 = 5\cdot x^{2}-18\cdot x + 17$

$4\cdot x^{2} -20\cdot x + 16 = 0$

$(2\cdot x)^{2} -10\cdot (2\cdot x) + 16 = 0$

$(2\cdot x -8)\cdot (2\cdot x -2) = 0$

There are two different solutions:

$x_{1} = 4$ , $x_{2} = 1$

A solution of $x$ is considered realistic when the length of every side of the triangle is a not negative number.

$x_{1} = 4$

$UV = 2\cdot (4) - 4$

$UV = 4$

$WU = 4 - 1$

$WU = 3$

$WV = 4 + 1$

$WV = 5$

$x_{2} = 1$

$UV = 2\cdot (1) - 4$

$UV = -2$

$WU = 1 - 1$

$WU = 0$

$WV = 1 + 1$

$WV = 2$

The only realistic set of solutions is for $x = 4$ , and the radius of the circle is represented by the line segment $WU$ : $r = 3$

And the area of the circle ( $A$ ) is calculated from the following formula:

$A = \pi\cdot r^{2}$

$A = \pi\cdot (9)$

$A = 9\pi$

The correct answer is C.

6 0

2 years ago

Last question! I need help with showing my work! I already have the answer in the attached image below, thanks!

Rainbow [258]

Answer:

see explanation

Step-by-step explanation:

Given

$\sqrt{\frac{4x^2}{3y} }$

= $\frac{\sqrt{4x^2} }{\sqrt{3y} }$

= $\frac{2x}{\sqrt{3y} }$

Rationalise the denominator by multiplying the numerator/ denominator by $\sqrt{3y}$

Note that $\sqrt{a}$ × $\sqrt{a}$ = a

= $\frac{2x}{\sqrt{3y} }$ × $\frac{\sqrt{3y} }{\sqrt{3y} }$

= $\frac{2x\sqrt{3y} }{3y}$

5 0

3 years ago