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3 years ago

Solve for |2x-8|=|x+3|

Mathematics

1 answer:

Ne4ueva [31]3 years ago

4 0

I hope this helps let me know in comments

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the class marks of a distribution are 37 42 and 47 the class limits corresponding to class mark 42 are

I am Lyosha [343]

Answer:

$39.5,44.5$

Step-by-step explanation:

$Let\ the\ lower\ limit\ and\ the\ upper\ limit\ of\ the\ first\ interval\ be\ u_1,v_1.\\Let\ the\ lower\ limit\ and\ the\ upper\ limit\ of\ the\ second\ interval\ be\ u_2,v_2.\\Let\ the\ lower\ limit\ and\ the\ upper\ limit\ of\ the\ third\ interval\ be\ u_3,v_3.\\Hence,\\As\ the\ class\ marks\ are\ uniform\ with\ an\ a\ difference\ of\ 5, the\\ observation\ is\ continuous\ and\ the\ class\ size\ is\ 5\ too.\\Hence,\\v_1=u_2, v_2=u_3\\$ $Now,\\Lets\ consider\ the\ first\ two\ classes.\\37=\frac{u_1+v_1}{2} \\42=\frac{u_2+v_2}{2}\\By\ adding\ the\ equations:\\79= \frac{u_1+v_1}{2}+\frac{u_2+v_2}{2}\\79=\frac{u_1+v_1+u_2+v_2}{2}\\79=\frac{(u_1+v_2)+(v_1+u_2)}{2}\\79=\frac{(u_1+v_2)}{2}+\frac{(v_1+u_2)}{2}\\Now,\\As\ the\ mid-point\ between\ two\ points\ can\ be\ calculated\ by\\ its\ average:\frac{u+v}{2} \\Hence,\\u_2\ lies\ in\ the\ mid-point\ of\ u_1\ and\ v_2.\\u_2=\frac{(u_1+v_2)}{2}\\$

$Hence,\\By\ substituting\ u_2=\frac{(u_1+v_2)}{2},\\79=u_2+\frac{v_1+u_2}{2}\\As\ v_1=u_2[Proven],\\79=u_2+ \frac{u_2+u_2}{2}\\79=u_2+\frac{2u_2}{2}\\79=2u_2\\Hence,\\u_2=\frac{79}{2}\\u_2=39.5\\Now,\ as\ we\ already\ know\ that\ the\ class\ size=5,\\v_2-u_2=5\\Hence,\\v_2=5+u_2\\Here,\\v_2=5+39.5\\v_2=44.5\\Hence,\\The\ upper\ limit\ of\ the\ second\ interval=44.5\\The\ lower\ limit\ of\ the\ second\ interval=39.5\\$

7 0

3 years ago

What’s 2+2 and 9+10 and 1x1

dem82 [27]

Answer:

2+2=4

9+10

1x1=1

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

6) Order from greatest to smallest: V2.1.40.11.14

leva [86]

Answer:

2nd first third first 1st last

Step-by-step explanation:

4 0

3 years ago

A committee that consists of five members are to be chosen from 6 boys and 5 girls. Find the number of different committees that

Maksim231197 [3]

Answer:

150 different committees can be formed

Step-by-step explanation:

We have 6 boys and 5 girls and we want to select 5 members

Out of these 5 members, two boys are selected

Since two boys are selected, we are left with three girls

So, out of 6 boys, we select 2 boys and out of 5 girls, we select 3 girls

Mathematically, we know that the number of ways in which we can select r items from a total n follows the combinatorial formula;

nCr = n!/(n-r)!r!

With this, we have;

6C2 * 5C3

= (6!/(6-2)!2!) * (5!/(5-3)!3!) = 150 different committees can be formed

3 0

3 years ago

I need help with that! Someone please help me

Elena L [17]

What is the question. it only says 7/12, 21/24, what does that mean?

6 0

3 years ago

Read 2 more answers