Answer:
g(-1 )=-1 and g(2)+g(1)=7
Step-by-step explanation:
If g(x) = x^3+x^2-x-2 find g(-1)
if we find g(-1)
we substitute all the x's in the function with -1
-1^3+-1^2-(-1)-2
-1^3 = -1
-1^2 = 1
-1+1+1-2
(two minuses make a plus)
-1+1 = 0
0+1 = 1
1-2 = -1
if x=-1, g(-1) is -1
g(2)+g(1)
substitute the x's in the function with 2 and 1 and add your results
2^3+2^2-2-2
2^3 = 8, 2^2 = 4
8+4-2-2
8+4= 12, 12-2 = 10, 10-2 = 8
g(2)=8
g(1) now
1^3 + 1^2-1-2
1^3=1, 1^2 = 1
1+1-1-2
1+1 = 2, 2-1 = 1, 1-2 = -1
g(3) = -1
g(2) (which equals 8) + g(3) (which equals -1) =
8+(-1) = 7
g(2)+g(3)=7
= [7+7 <span>÷ 7] + 4.12
= [7+1] + 4.12
= 8 + 4.12
= 12.12
</span>
Answer:

Step-by-step explanation:
assuming the recurring digits are 0.272727.... , then
we require 2 equations with the repeating digits placed after the decimal point.
let x = 0.2727.... (1) ← multiply both sides by 100
100x = 27.2727... (2)
subtract (1) from (2) thus eliminating the repeating digits
99x = 27 ( divide both sides by 99 )
x =
=
← in simplest form
For question 2 it is 15
Because: 4 time 6 is 24 and then you minus 9 which is 15
So there you have it the answer is 15
Answer:
<h2>Multiplication.</h2>
Step-by-step explanation:
The given expression is

For
, we have

Notice that the first operation we need to do is multiplication, because that's the right order of operations when we solve these kind of expressions.

Then, we subtract

Now, we divide

Finally, we sum

Therefore, the right answer is multiplication.