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2 years ago

8

Nadia selects three marbles from the jar to the right without replacing them. What is the probability that all three marbles are

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1 answer:

Savatey [412]2 years ago

4 0

Not very likely. Does a picture come with this question.

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Review the steps of the proof.

lana [24]

Answer:

steps 2 and 3 must be switched

Step-by-step explanation:

e2020

7 0

2 years ago

Read 2 more answers

A basket contains 12 apples and some other fruit. Write an equation that could be used to find the total number of fruits in the

o-na [289]

A basket contains 12 apples and some other fruit
40% of the total fruit are apples...so 40% of the total fruit is 12..

0.40x = 12....with x being the total fruit in the basket <== ur equation
x = 12 / 0.40
x = 30....and u have 30 pieces of fruit in the basket

7 0

2 years ago

Use the substitution method

vitfil [10]

Answer:

z = 9

z = 2

z = 5

z = 8

z = 11

Step-by-step explanation:

5 0

2 years ago

What is the sum or difference of 5/7 - 1/3

Hatshy [7]

ANSWER: 8/21

Step:
1. Find the GCF (Greatest Common Factor)
The two denominator which is the bottom number have to be the same ALWAYS when adding and subtracting the fraction. So to find the GCF, you keep multiplying until you see the same number, only use the bottom number to find the GCF
7: 7, 14, 21, 28
3: 3, 6, 9, 12, 15, 18, 21, 24, 27
GCF= 21

2. 5/7 -1/3
Multiple both to get 21
5/7 x 3/3 = 15/21
1/3 x 7/7 = 7/21

3. Sove
15/21 - 7/21
= 8/21

7 0

2 years ago

The probability that a randomly chosen citizen-entity of Cygnus is of pension age† is approximately 0.7. What is the probability

victus00 [196]

Answer: 0.2401

Step-by-step explanation:

The binomial distribution formula is given by :-

$P(x)=^nC_xp^x(1-p)^{n-x}$

where P(x) is the probability of x successes out of n trials, p is the probability of success on a particular trial.

Given : The probability that a randomly chosen citizen-entity of Cygnus is of pension age† is approximately: p =0.7.

Number of trials : n= 4

Now, the required probability will be :

$P(x=4)=^4C_4(0.7)^4(1-0.7)^{4-4}\\\\=(1)(0.7)^4(1)=0.2401$

Thus, the probability that, in a randomly selected sample of four citizen-entities, all of them are of pension age =0.2401

5 0

2 years ago