At point of intersection the two equations are equal,
hence, 6x³ =6x²
6x³-6x²=0
6x²(x-1)=0 , the values of x are 0 and 1
The points of intersection are therefore, (0,0) and (1,6)
To find the slopes of the tangents at the points of intersection we find dy/dx
for curve 1, dy/dx=12x, and the other curve dy/dx=18x²
At x=0, dy/dx=12x =0, dy/dx=18x² = 0, hence the angle between the tangents is 0, because the tangents to the two curves have the same slope which is 0 and pass the same point (0,0) origin.
At x=1, dy/dx =12x = 12, dy/dx= 18x² =18, Hence the angle between the two tangents will be given by arctan 18 -arctan 12
= 86.8202 - 85.2364 ≈ 1.5838, because the slope of the lines is equal to tan α where α is the angle of inclination of the line.
Answer:
86°
Step-by-step explanation:
- Angles on a straight line add up to 180° always
180° - 94° = x° = 86°
Answer: see image
<u>Step-by-step explanation:</u>
Count how many spaces the vertex is away from the line x = -1. Then place that vertex the same distance on the other side of the line x = -1.
Change the ratios to decimals and compare:
7 / 12 = 0.583
7 / 8 = 0.875
So 7:12 is less than 7/8
The answer is <
