Make fractions equal by writing a number in each box (equivalent) 1/2 = / = / = / = / = /

Mathematics

2 answers:

Lana71 [14]2 years ago

7 0

1/2=2/4=4/8=5/10=6/12=7/14 Hope it helps :)

Grace [21]2 years ago

5 0

1/2 = 2/4 = 3/6 = 4/8 = 5/10 = 6/12

Let's think of this visually, as a pie.
If you were to split a pie down the middle into two pieces and ate one slice, you would be eating half of it.
Now, let's say you didn't eat one of those slices. You sliced the pie down the middle (vertically) and made another slice (horizontally). You would have 4 equal pieces. If you ate two slices that were side by side, you would still have had the same amount if you just sliced it once. If you were to keep slicing and eating, you'd be eating the same amount if you kept it to two pieces.
Hope it helped!

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There is 1/3 gallon of water in a 3-gallon container. Write a multiplication AND a division equation to represent the situation.

iogann1982 [59]

Answer:

1/3

Step-by-step explanation:

1×3÷3=1/3

8 0

2 years ago

Read 2 more answers

If f(x)=2x+sinx and the function g is the inverse of f then g'(2)=

Alexxx [7]

$\bf f(x)=y=2x+sin(x)
\\\\\\
inverse\implies x=2y+sin(y)\leftarrow f^{-1}(x)\leftarrow g(x)
\\\\\\
\textit{now, the "y" in the inverse, is really just g(x)}
\\\\\\
\textit{so, we can write it as }x=2g(x)+sin[g(x)]\\\\
-----------------------------\\\\$

$\bf \textit{let's use implicit differentiation}\\\\
1=2\cfrac{dg(x)}{dx}+cos[g(x)]\cdot \cfrac{dg(x)}{dx}\impliedby \textit{common factor}
\\\\\\
1=\cfrac{dg(x)}{dx}[2+cos[g(x)]]\implies \cfrac{1}{[2+cos[g(x)]]}=\cfrac{dg(x)}{dx}=g'(x)\\\\
-----------------------------\\\\
g'(2)=\cfrac{1}{2+cos[g(2)]}$

now, if we just knew what g(2) is, we'd be golden, however, we dunno

BUT, recall, g(x) is the inverse of f(x), meaning, all domain for f(x) is really the range of g(x) and, the range for f(x), is the domain for g(x)

for inverse expressions, the domain and range is the same as the original, just switched over

so, g(2) = some range value
that means if we use that value in f(x), f( some range value) = 2

so... in short, instead of getting the range from g(2), let's get the domain of f(x) IF the range is 2

thus 2 = 2x+sin(x)

$\bf 2=2x+sin(x)\implies 0=2x+sin(x)-2
\\\\\\
-----------------------------\\\\
g'(2)=\cfrac{1}{2+cos[g(2)]}\implies g'(2)=\cfrac{1}{2+cos[2x+sin(x)-2]}$

hmmm I was looking for some constant value... but hmm, not sure there is one, so I think that'd be it

5 0

2 years ago

I really need help with this question. Can I get a explanation too?

aniked [119]

Answer:

Step-by-step explanation:

Find the surface area:

Bottom base: 57 × 27 = 1,539

Top base: 21 × 27 = 567

Rectangular face: 23 × 27 = 621

Trapezoidal face: (21 + 57) ÷ 2 × 15 = 585

1,539 + 567 + 621 + 621 + 585 + 585 = 4,518