0. A local lawn service charges $6.00 per cut plus $2.50 per gallon of gas

Mathematics

1 answer:

xenn [34]4 years ago

3 0

Answer:

C = 6 + 2.5g

Step-by-step explanation:

A local lawn service charges $6.00 per cut plus $2.50 per gallon of gas used.

If in a cut g gallons of gas is used then, the cost for gas used will be $2.5g and there is a fixed charge of $6.00 per cut.

Therefore, in total the cost per cut becomes 6 + 2.5g and if we represent the total cost as C, then we can write

C = 6 + 2.5g. (Answer)

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Sonbull [250]

2x^2 - 7x - 6 = 0

$x1 = \frac{- b + \sqrt{ {b}^{2} - 4ac }}{2a}$
$x2 = \frac{- b - \sqrt{ {b}^{2} - 4ac }}{2a}$
where a=2
where b=-7
where c=-6

solve for x1 and x2

x1=4.21
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6 0

3 years ago

Prove that DJKL~ DJMN using SAS Similarity Theorem. Plot the points J (1,1), K(2,3), L(4,1) and J (1,1), M(3,5), N(7,1). Draw DJ

dolphi86 [110]

Answer and Step-by-step explanation: The triangles are plotted and shown in the attachment.

SAS Similarity Theorem is by definition: if two sides in one triangle are proportional to two sides of another triangle and the angles formed by those sides in each triangle is congruent, the triangles are similar.

For the triangles on the grid, we know that ΔJKL and ΔJMN have a congruent angle in J as shown in the image. To prove they are similar, we find the slope of sides KL and MN:

Slope of KL:

slope = $\frac{y_{K} - y_{L} }{x_{K} - x_{L} }$

slope = $\frac{3-1}{2-4}$

slope = -1

Slope of MN:

slope = $\frac{y_{N} - y_{M} }{x_{N} - x_{M} }$

slope = $\frac{1-5}{7-3}$

slope = -1

Since the slopes of KL and MN are the same and the angle is congruent, we can conclude that ΔJKL~ΔJMN.

5 0

3 years ago

Solve the quadratic equation by completing the square. x²–2x-12=0

inn [45]

Answer:

$(x-1)^2-13=0$

$x = \sqrt{13}+1$

Step-by-step explanation:

Completing the square is a method of rewriting a quadratic equation in the standard form such that it is in vertex form. The first step is to group the linear and quadratic terms, then factor out the coefficient of the quadratic term. After doing so, complete the square, add a value such that the linear and quadratic terms form a perfect square trinomial. Do not forget to balance the equation. The final step is to simplify.

$x^2-2x-12=0$