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ANEK [815]
3 years ago
13

PLEASE HELP QUICK, I NEED IT

Mathematics
2 answers:
melisa1 [442]3 years ago
8 0
We take the equation <span>d = -16t^2+12t</span> and subtract d from both sides to get
                                         0<span> = -16t^2+12t - d
We apply the quadratic formula to solve for t. With a = -16, b = 12, c = -d, we have
                                         t = [ -(12) </span><span>± √( 12^2 - 4(-16)(-d) ) ] / [2 * -16]</span>
                                           = [- 12 ± √(144-64d) ] / (-32)
                                           = [- 12 ± √16(9-4d)] / (-32)
                                           = [- 12 ± 4√(9-4d)] / (-32)
                                           = 3/8 ±√(9-4d) / 8
The answer to your question is t = 3/8 ±√(9-4d) / 8
babymother [125]3 years ago
8 0

Here are a bunch of CORRECT answers. Your answer is in the last pic. I got number 3 wrong, but it still showed the correct answer.

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Evaluate the quantity 3 squared times 3 to the power of negative 5 end quantity over 5 to the power of negative two.
chubhunter [2.5K]

The value of the expression given as  [3² * 3⁻⁵]/[5⁻²] is 25/27

<h3>How to evaluate the expression?</h3>

The expression is given as:

3 squared times 3 to the power of negative 5 end quantity over 5 to the power of negative two

Rewrite properly as:

[3² * 3⁻⁵]/[5⁻²]

Apply the negative exponent law of indices

So, we have

[3² * 3⁻⁵]/[5⁻²] = [5²]/[3⁻² * 3⁵]

Apply the exponent law of indices

[3² * 3⁻⁵]/[5⁻²] = [5²]/[3³]

This gives

[3² * 3⁻⁵]/[5⁻²] = 25/27

Hence, the value of the expression given as  [3² * 3⁻⁵]/[5⁻²] is 25/27

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brainly.com/question/723406

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1 year ago
A quantity, y, varies directly as x When y=10, x=6.<br> Find xwhen y= 14.
grigory [225]

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<h3 />

<h3>How to solve variation ?</h3>

y, varies directly as x. Therefore,

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Therefore,

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Therefore,

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Hence, when y = 14

y = kx

14 = 5 / 3 x

cross multiply

42 = 5x

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x = 8.4

learn more on variation here: brainly.com/question/20707320

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