Answer:
sounds like a relationship problem
Step-by-step explanation:
that cheating wont fix.
A triangle needs to add up to 180 degrees so 44 plus 37 is 81 so that last angle is 99 degrees then you do 180 minus that angle because those 2 angles need to equal up so not equals 81
Answer:
The option B is the correct answer. 79.18 m²
Step-by-step explanation:
Surface area = Base area + Lateral surface area
Area of triangle = bh/2
b - base and h - height
<u>To find the base area</u>
We can consider the base is a hexagon.
A regular hexagon is a combination of 6 equilateral triangle
Base area = 6 * area of triangle
base b = 3
<u>To find the height</u>
h =√[(6.2)² - (5.6)₂] = 2.7
Area of triangle bh/2 = (3 * 2.7)/2 = 3.99
Area of base = 23.95
To find lateral surface area
Lateral surface area = 6 * area of triangle
Area of triangle = bh/2 =(3 *6.2)/2 = 9.3
Lateral surface area = 6 * 9.3 = 55.8
<u>To find the total surface area </u>
Total surface area = Base area + lateral surface area = 23.95 + 55.8
= 79.75 m²
Therefore the option B is the correct answer. 79.18 m²
The computation shows that the placw on the hill where the cannonball land is 3.75m.
<h3>How to illustrate the information?</h3>
To find where on the hill the cannonball lands
So 0.15x = 2 + 0.12x - 0.002x²
Taking the LHS expression to the right and rearranging we have:
-0.002x² + 0.12x -.0.15x + 2 = 0.
So we have -0.002x²- 0.03x + 2 = 0
I'll multiply through by -1 so we have
0.002x² + 0.03x -2 = 0.
This is a quadratic equation with two solutions x1 = 25 and x2 = -40 since x cannot be negative x = 25.
The second solution y = 0.15 * 25 = 3.75
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Complete question:
The flight of a cannonball toward a hill is described by the parabola y = 2 + 0.12x - 0.002x 2 . the hill slopes upward along a path given by y = 0.15x. where on the hill does the cannonball land?
Answer:
10 servings
Step-by-step explanation:
5 pound= 80 ounce
80/8=10
10