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3 years ago

Solve triangle ABC, when A= 6, B=10 and c=12

1 answer:

5 0

Use cosine rule,

cos(A)=(b^2+c^2-a^2)/(2bc)
=(10^2+12^2-6^2)/(2*10*12)
=13/15
A=29.926 degrees.................................(A)

cos(B)=(c^2+a^2-b^2)/(2ca)
=(12^2+6^2-10^2)/(2*12*6)
=5/9
B=56.251 degrees.................................(B)

cos(C)=(a^2+b^2-c^2)/(2ab)
=(6^2+10^2-12^2)/(2*6*10)
=-1/15
C=93.823 degrees.................................(C)

Check:29.926+56.251+93.823=180.0 degrees....ok

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netineya [11]

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2 years ago

Li walks at a constant rate of 7 ft. in 4 seconds. The table shows the relationship of feet to seconds. What is the constant of

Kisachek [45]

Answer:

The rate is 1.75 feet/seconds or 105 feet/minute.

Step-by-step explanation:

Given that,

Li walks at a constant rate of 7 feet in 4 seconds

To find the constant of proportionality, divide 7 feet by 4 seconds.

So,

$k=\dfrac{7\ \text{feet}}{4\ \text{seconds}}\\\\k=1.75\ \text{ft/s}$

1.75 ft/s is the constant of proportionality

We know that, 1 minute = 60 seconds

k = 105 feet/minute

So, the rate is 1.75 feet/seconds or 105 feet/minute.

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3 years ago

algol [13]

Answer:

Step-by-step explanation:

We have the two functions:

$f(x)=\sqrt{x}+12\text{ and } g(x)=2\sqrt{x}$

And we want to find (f-g)(144).

This is the same thing to f(144)-g(144).

So, let’s determine the value of f(144) and g(144) first:

$\begin{aligned} f(144)&=\sqrt{144}+12 \\ &=12+12 \\ &=24\end{aligned}$

And:

$\begin{aligned} g(144)&=2\sqrt{144} \\ &=2(12) \\ &=24 \end{aligned}$

Hence:

$\begin{aligned} (f-g)(144) &= f(144)-g(144) \\ &=24-24 \\ &=0 \end{aligned}$

Our final answer is 0.

6 0

3 years ago

Read 2 more answers

U - 4u + 4 = 7 what is U

valentina_108 [34]

Try to get the u’s on one side so for this to happen, you would subtract the four from both sides.
u - 4u = 7 - 4

combine like terms

-3u = 3

divide by -3

u = -1

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3 years ago

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Find the value of c that completes the square for x2+12x+c .

maw [93]

The answer is =x2+c+12x

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2 years ago