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3 years ago

Solve triangle ABC, when A= 6, B=10 and c=12

1 answer:

5 0

Use cosine rule,

cos(A)=(b^2+c^2-a^2)/(2bc)
=(10^2+12^2-6^2)/(2*10*12)
=13/15
A=29.926 degrees.................................(A)

cos(B)=(c^2+a^2-b^2)/(2ca)
=(12^2+6^2-10^2)/(2*12*6)
=5/9
B=56.251 degrees.................................(B)

cos(C)=(a^2+b^2-c^2)/(2ab)
=(6^2+10^2-12^2)/(2*6*10)
=-1/15
C=93.823 degrees.................................(C)

Check:29.926+56.251+93.823=180.0 degrees....ok

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Please solve B, C, D, E, and F and I will give Brainliest!

kykrilka [37]

Answer:

a. 125

b. 25/64

c. 0.25

d. 343

e. 49/4

f. 0.81

Step-by-step explanation:

multiply by the same number by the amount of times the power tells you

b. 5*5 = 25 8*8= 64

c. 5*5 = 25 0.5*0.5 = 0.25

d. 7*7*7 = 343

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2 years ago

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3 years ago

Complete the coordinate proof of the theorem. Given: A B C D is a rectangle. Prove: The diagonals of A B C D are congruent.

Inessa05 [86]

Step-by-step explanation:

Given coordinates of the rectangle ABCD:

A(0, 0), B(a, 0), C(x, y), D(0, b)

Lets first find coordinates of C

We can see that A and B are on same line horizontally, so C and D will be on the parallel line

The distance AB and CD are equal also distance AD and BC are equal, therefore

AB = a - 0 = a, CD = a
AD = b - 0 = b, BC = b

So the coordinates of C are:

x = a, y = b

Now the diagonals:

AC = √(a-0)² + (b-0)² = √a²+b²
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Since AC = BD, we can state they are congruent

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3 years ago

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