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3 years ago

Area: Trapezoids, Rhombuses, Kites. It says perimeter but I just need the Area please

Mathematics

1 answer:

user100 [1]3 years ago

6 0

Area: Trapezoids A = ½h(b1 + b2)
Rhombuses A=pq/2
Kites A=pq/2

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One container is filled with mixture that is 25% acid. A second container is filled with a mixture that is 55% acid. The second

algol13

Answer:

Therefore the third container contains $\frac{735}{17}\%$ = 43.23 % acid.

Step-by-step explanation:

Given that, One container is filled with the mixture that 25% acid. 55% acid is contain by second container.

Let the volume of first container be x cubic unit.

Since the volume of second container is 55% larger than the first.

Then the volume of the second container is

$= (V\times \frac{100+55}{100})$ cubic unit.

$=\frac{155}{100}V$ cubic unit.

The amount of acid in first container is

$=V\times \frac{25}{100}$ cubic unit.

$=\frac{25}{100}V$ cubic unit.

The amount of acid in second container is

$=(\frac{155}{100}V \times \frac{55}{100})$ cubic unit.

$=\frac{8525}{10000}V$ cubic unit.

Total amount of acid $=(\frac{25}{100}V+\frac{8525}{10000}V)$ cubic unit.

$=(\frac{2500+8525}{10000}V)$ cubic unit.

$=(\frac{11025}{10000}V)$ cubic unit.

Total volume of mixture $=(V+\frac{155}{100}V)$ cubic unit.

$=\frac{100+155}{100}V$ cubic unit.

$=\frac{255}{100}V$ cubic unit.

The amount of acid in the mixture is

$=\frac{\textrm{The volume of acid}}{\textrm{The amount of mixture}}\times 100 \%$

$=\frac {\frac{11025}{10000}V}{\frac{255}{100}V}\times 100\%$

$=\frac{735}{17}\%$

Therefore the third container contains $\frac{735}{17}\%$ acid.

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3 years ago

If i have 35% of a phones and its now $78 how much was the phone before the discount

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Step-by-step explanation:

Multiply $78 by by 65/100 to determine the original price.

78 can be put over 1.

Multiply:

$\frac{78}{1} \times \frac{65}{100} = \frac{5070}{100}$

Simplify by dividing the numerator and denominator by 100:

$\frac{5070 \div 100}{100 \div 100} = \frac{50.70}{1}$

The original price was $50.70.

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Answer:

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