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3 years ago

3x+y=1 then graph the linear equation and label the y-intercept

Mathematics

1 answer:

Phantasy [73]3 years ago

5 0

Answer:

y-int: 1

slope: 3 (#before x)

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Mrs. Ishimitsu is installing a rubber bumper around the edge of her coffee table. The dimensions of the rectangular table are (2

ollegr [7]

Answer:

$2x^2+8x-30$ represents the total perimeter of the table, and if x = 3 the lentgh of entire rubber bumper is 12 feet.

Step-by-step explanation:

Perimeter is defined as the sum of sides.

For a rectangle having dimension length 'L' and breadth 'B' Since, rectangle has two sides equal.

Perimeter of rectangle = 2 ( length + breadth )

Here, given rectangle has dimension

Length = $2x^2-16$ and breadth = $-x^2+4x+1$

Thus, perimeter of rectangle = $2(2x^2-16+(-x^2+4x+1))$

$=2(2x^2-16-x^2+4x+1)$

$=2(x^2+4x-15)$

$=2x^2+8x-30$

Thus, perimeter of rectangle is $2x^2+8x-30$ ........(1)

Perimeter of rectangle , when x = 3,

Put x= 3 in (1) ,

$2x^2+8x-30\Rightarrow 2(3)^2+8(3)-30 \Rightarrow 18+24-30=12$

Thus, $2x^2+8x-30$ represents the total perimeter of the table, and if x = 3 the lentgh of entire rubber bumper is 12 feet.

5 0

3 years ago

Read 2 more answers

Can someone double-check whether I am right or wrong?

Ludmilka [50]

You’re right, both of the pairs are similar

4 0

2 years ago

Os It true<br> 0.9 is 1/10 of 0.09

goldfiish [28.3K]

Yes it is add a zero to it as the tenth powers increases

6 0

3 years ago

Determine the slope of the line that passes through each pair of points.

Soloha48 [4]

$1.)\\\\(5,1) \ \ and \ \ (2,7)\\\\First \ find \ the \ slope \ of \ the \ line \ thru \ the \ points \: \\ \\ m= \frac{y_{2}-y_{1}}{x_{2}-x_{1} } \\ \\m=\frac{ 7-1}{2-5} = \frac{6}{-3}=-2 \\ \\ Use \ point \ form \ of \ a \ line\ with \ one \ point: \\ \\ y-y_{1} =m(x-x _{1}) \\ \\m=-2 , \ \x_{1}=5, \ \ y_{1}=1 \\ \\y-1 = -2(x-5 ) \\\\y=-2x+10+1 \\ \\y=-2x+11$

$2.)\\\\(5,3)\ \ and \ \ (-2,3)\\\\First \ find \ the \ slope \ of \ the \ line \ thru \ the \ points \: \\ \\ m= \frac{y_{2}-y_{1}}{x_{2}-x_{1} } \\ \\m=\frac{ 3-3}{-2-5} = \frac{0}{-7}=0\\ \\ Use \ point \ form \ of \ a \ line\ with \ one \ point: \\ \\ y-y_{1} =m(x-x _{1}) \\ \\m=0 , \ \x_{1}=5, \ \ y_{1}=3 \\ \\y-3 = 0\cdot (x-5 ) \\\\y-3=0 \\ \\y=3$

7 0

3 years ago

Can anybody help me please

Burka [1]

(7,1) is the correct answer

7 0

3 years ago

Read 2 more answers