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2 years ago

Which shows the correct substitution of the values a, b, and c from the equation 1 = –2x + 3x2 + 1 into the quadratic formula?

Mathematics

2 answers:

inn [45]2 years ago

7 0

Answer:

the answer is A on edg

Alchen [17]2 years ago

6 0

$1=-2x+3x^2+1\\\\3x^2-2x+1-1=0\\\\3x^2-2x=0\\\\\boxed{a=3;\ b=-2;\ c=0}$

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Evaluate the expression described below if the number is 4. The difference between a number squared and the number. A. 0 B. 4 C.

svet-max [94.6K]

What the above statement is saying is:
If the number is 4, find the difference between the square of the number (the number is 4) and the number itself (the number is still 4).

The square of the number is:
The number^2
= 4^2
= 4 × 4
= 16

The difference between the square of the number and the number is:
The number^2 - The number
= 16 - 4
= 12

Hope this helps! :)

5 0

3 years ago

There are 99 males and 121 females participating in a marathon. What percent of the participants are female?

ioda

To do this, we first want to see how many participants there are in total by adding both males and females.

$99+121=220$

Now we know that there were 220 total participants, but only 121 were females.

This allows us to set up the fraction 121/220= the percent female.

$\frac{121}{220} =0.55$

or 55%

8 0

2 years ago

HELP ME QUICK PLEASEEEE solve for x: 2/x-2+7/x^2-4=5/x

Anna35 [415]

$\displaystyle\\\\\frac{2}{x-2}+\frac{7}{x^2-4}=\frac{5}{x}\\\\\frac{^{x+2)}2~~~~~}{x-2}+\frac{7}{(x-2)(x+2)}=\frac{5}{x}\\\\\frac{2(x+2)}{(x-2)(x+2)}+\frac{7}{(x-2)(x+2)}=\frac{5}{x}\\\\\frac{2x+4+7}{x^2-4}=\frac{5}{x}\\\\\frac{2x+11}{x^2-4}=\frac{5}{x}\\\\5(x^2-4)=x(2x+11)\\\\5x^2-20=2x^2+11x\\\\5x^2-2x^2 -11x-20=0$

$\displaystyle\\3x^2-11x-20=0\\\\x_{1,2}=\frac{-b\pm\sqrt{b^2-4ac}}{2a}=\frac{11\pm\sqrt{121+4\cdot3\cdot20}}{2\cdot3}=\\\\=\frac{11\pm\sqrt{121+240}}{6}=\frac{11\pm\sqrt{361 }}{6}=\frac{11\pm19}{6}\\\\x_1=\frac{11-19}{6}=\frac{-8}{6}\\\\\boxed{\bf x_1=-\frac{4}{3}}\\\\x_2=\frac{11+19}{6}=\frac{30}{6}\\\\\boxed{\bf x_2=5}$

3 0

3 years ago

A life guard in a tower 20 ft above sea level spots a struggling surfer at an angle of depression of 15 . How far is the surfer

GalinKa [24]

Answer: $19.31\ ft$

Step-by-step explanation:

Given

The tower is at a height of $h=20\ ft$

the angle of depression is $15^{\circ}$

Suppose the surfer is x ft away from the base of the tower

$\therefore \text{From the figure, we can write}\\\\\Rightarrow \cos 15^{\circ}=\dfrac{x}{h}\\\\\Rightarrow x=h\cos 15^{\circ}\\\Rightarrow x=20\cos 15^{\circ}\\\Rightarrow x=19.31\ ft$

Therefore, the surfer is at a distance of 19.31 ft from the base of the tower.

7 0

2 years ago

Can you please fill in the blank? A fraction is a number that represents part of a ________. I know this is an easy question, bu

strojnjashka [21]

Equation because then you need to divide and multiply

7 0

2 years ago

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