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Fill in the blank. A _______ probability of an event is a probability obtained with knowledge that some other event has already

motikmotik

Answer:

A conditional probability of an event is a probability obtained with knowledge that some other event has already occurred.

Step-by-step explanation:

Conditional probability of an event (A) is a probability obtained with knowledge that some other event (B) has already occurred and is denoted as P(A|B).

It satisfies the following equation:

P(A|B)=P(A and B) / P(B)

where P(A and B) is the probability of A and B occurring together.

Conditional probability is applied in many areas of Bayesian statistics and machine learning.

3 0

3 years ago

An HP printer costs $180, with printing costs of $0.03 per page. A Samsung printer costs $230, with printing costs of $0.01 per

Softa [21]

Answer:

2,500 pages

Step-by-step explanation:

Let

y -----> the overall cost

x -----> the number of pages

we know that

HP printer

$y=0.03x+180$ ------> equation A

Samsung printer

$y=0.01x+230$ -----> equation B

Solve the system by substitution

Substitute equation B in equation A

$0.03x+180=0.01x+230$

Solve for x

$0.03x-0.01x=230-180\\0.02x=50\\x=2,500\ pages$

8 0

3 years ago

A student at a four-year college claims that mean enrollment at four-year colleges is higher than at two-year colleges in the Un

WINSTONCH [101]

Answer:

Part 1: The statistic

$t=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{\sigma^2_{1}}{n_{1}}+\frac{\sigma^2_{2}}{n_{2}}}}$ (1)

And the degrees of freedom are given by $df=n_1 +n_2 -2=35+35-2=68$

Replacing we got

$t=\frac{(5135-4436)-0}{\sqrt{\frac{783^2}{35}+\frac{553^2}{35}}}}=4.31$

Part 2: P value

Since is a right tailed test the p value would be:

$p_v =P(t_{68}>4.31)=0.000022 \approx 0.00002$

Comparing the p value we see that is lower compared to the significance level of 0.01 so then we can reject the null hypothesis and we can conclude that the mean for the four year college is significantly higher than the mean for the two year college and then the claim makes sense

Step-by-step explanation:

Data given

$\bar X_{1}=5135$ represent the mean for four year college

$\bar X_{2}=4436$ represent the mean for two year college

$s_{1}=783$ represent the sample standard deviation for four year college

$s_{2}=553$ represent the sample standard deviation two year college

$n_{1}=35$ sample size for the group four year college

$n_{2}=35$ sample size for the group two year college

$\alpha=0.01$ Significance level provided

t would represent the statistic (variable of interest)

System of hypothesis

We need to conduct a hypothesis in order to check if the mean enrollment at four-year colleges is higher than at two-year colleges in the United States , the system of hypothesis would be:

Null hypothesis: $\mu_{1}-\mu_{2}\leq 0$

Alternative hypothesis: $\mu_{1} - \mu_{2}> 0$

We can assume that the normal distribution is assumed since we have a large sample size for each case n>30. So then the sample mean can be assumed as normally distributed.

Part 1: The statistic

$t=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{\sigma^2_{1}}{n_{1}}+\frac{\sigma^2_{2}}{n_{2}}}}$ (1)

And the degrees of freedom are given by $df=n_1 +n_2 -2=35+35-2=68$

Replacing we got

$t=\frac{(5135-4436)-0}{\sqrt{\frac{783^2}{35}+\frac{553^2}{35}}}}=4.31$

Part 2: P value

Since is a right tailed test the p value would be:

$p_v =P(t_{68}>4.31)=0.000022$

Comparing the p value we see that is lower compared to the significance level of 0.01 so then we can reject the null hypothesis and we can conclude that the mean for the four year college is significantly higher than the mean for the two year college and then the claim makes sense

6 0

3 years ago

PLEASE HELP(will mark brainiest) Draw a quadrilateral A'B'C'D' that is a translation (x + 2, y - 4) of quadrilateral ABCD.

yuradex [85]

Answer:

New coordinates:

A: (2,-4)

B: (6,-4)

C: (7,1)

D: (3,1)

Step-by-step explanation:

You translate each of the starting coordinates by adding or subtracting them by the coordinates given.

x coordinates: 0+2=2 y coordinates: 0-4= -4

4+2=6 0-4= -4

5+2=7 5-4= 1

1+2=3 5-4= 1

7 0

3 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=y%20%3D%204%20%28%5Cfrac%7B1%7D%7B2%7D%29%5E%7B2%7D%20" id="TexFormula1" title="y = 4 (\frac{1

poizon [28]

Solve using PEMDAS (Parenthesis, Exponent, Multiply, Divide, Add, Subtract) to find Y

Solve Exponent first
1/2^2 = 0.25

Multiply
4 x 0.25 = 1
y = 1

3 0

3 years ago