2x^3 + 9x - 8 - (4x^2 - 15x + 7)....distribute thru the parenthesis
2x^3 + 9x - 8 - 4x^2 + 15x - 7....combine like terms
2x^3 - 4x^2 + 24x - 15 <==
Answer:
(5 x + 1) - (-10 x + 6)
5x +1 + 10x - 6
25x - 5
Step-by-step explanation:
(x - 2) - (6x - 9)
x - 2 - 6x + 9 =
-5x +7
(5 x + 1) - (-10 x + 6)
5x +1 + 10x - 6
25x - 5
-4 x + 2 x + 7 - 3 x
-5x + 7
(4 x + 3) + (-9 x + 4)
4x +3 -9x + 4
-5x + 7
First, let's subtract both sides by 4:
|2x - 3| = 13
We can get two different equations from this:
2x - 3 = 13
and
2x - 3 = -13
So:
2x = 16
2x = -10
x = 8, x = -5
The solution set is {8, -5}
Answer:
Step-by-step explanation:
b
2x + y - 4 = 0
We need to first rearrange this so y is the subject
Can you do that or u need help