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irina1246 [14]
2 years ago
5

Martin earn the following scores on his last five test. What is the interquartile of his course

Mathematics
2 answers:
Dmitriy789 [7]2 years ago
5 0

Answer:

18

Step-by-step explanation:

The interquartile range is the middle 50% of the data.

To find the interquartile range,  we must first find the lower and upper quartiles.

In this case, the lower quartile is 76.5, and the upper quartile is 94.5.

Subtracting 76.5 from 94.5 gives us the answer of 18.

Let me know if this helps!

kap26 [50]2 years ago
4 0
I also think that it is 18
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nate went shopping at a bookstore. the price of a book was 14.95 but it had a sale sticker. when he paid for it he was charged 1
juin [17]
The sales percent was 15% off
4 0
3 years ago
Which of the expressions are equivalent to the one below? 5x(3+7)
MArishka [77]

3×(2+6)+4×5 is/= 44,

3×2+3×6+4×5=44

5×4+3×(6+2)=44

(6+2)×3+4×5=44

3×2+(6+4)×5= 56

So your answers are A, B, and C.

Step-by-step explanation:

..Calculator

6 0
2 years ago
Read 2 more answers
jerry is a judge. He hears 5 cases every 2 3/8 hours. Jerry hears caese at a constant rat. How many cases does he hear per hour
faust18 [17]

Answer:

The number of cases heard by Jerry per hour is 2\frac{21}{500}

Step-by-step explanation:

The rate of hearing the cases is 5 cases in 2 3/8 hours.

Now, 2\frac{3}{8}   = 2+\frac{3}{8}  = 2 + 0.375 = 2.375

⇒The judge hears 5 cases in 2.375 hours.

So, the number of cases per hour = = \frac{\textrm{Total Number of cases heard}}{\textrm{Number of Hours}}  = \frac{5}{2.375}

                                                           = 2.105

Also, 2.105 =   2 + 0.105 =  2 + \frac{105}{1000}   = 2+\frac{21}{500}  = 2\frac{21}{500}

Hence, the number of cases heard by Jerry per hour is 2\frac{21}{500}

8 0
3 years ago
NEED HELP ASAP, WILL MARK BRAINLIEST!!!
EastWind [94]

Answer:

7. -

a. 3.5 or 7/2 hours

b. 24.5

c. After 7 hours (and at the beginning when t=0)

8. -

a. 4 seconds

b. 1 second

c. 54 meters

Step-by-step explanation:

7. M(t)=-2t^2+14t

M’(t)=-4t+14

a)

-4t+14=0

4t=14

2t=7

t=7/2

b) M(7/2)=24.5

c)

M(t)=0

-2t^2+14t=0

t^2-7t=0

t(t-7)=0

t=0, 7

8.

a)

h(t)=0

-6t^2+12t+48=0

t^2-2t-8=0

(t-4)(t+2)=0

t=-2, 4

t=4

b)

h(t)=-6t^2+12t+48

h’(t)=-12t+12

h’(t)=0

-12t+12=0

12t=12

t=1

c) h(1)=54

I hope this helps; please vote brainliest!

3 0
3 years ago
Please help me with this
3241004551 [841]
Exponential Function

8 0
3 years ago
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