Since it's a wall, I'm guessing it will only have access to half the circle? Therefore:
<em>Circle area formula: </em>πr²
<em>Radius:</em> 12/2 = 6ft
<em>Our case:</em>
(π * 6²)/2 =
36π/2 =
18π = 56.55ft²
Answer:
x = k - 3
Step-by-step explanation:
Given parameters:
Gradient of the line = 5;
Coordinates; M(x, 8)
N(k, 23)
Solution:
If we use the expression for finding the slope of the line, we can solve this problem;
Slope = 
where
x₁ = x y₁ = 8
x₂ = k y₂ = 23
Input the parameters:
5 = 
15 = 5(k - x)
3= k- x
k - x = 3
Express x in terms of k;
-x = 3 - k
Multiply through by -1;
x = -3 + k
x = k - 3
The error in Jerry's calculation is 4.84
The number of employees, N = 4
The mean is calculated as:

The formula for the standard deviation is:

This can be further calculated as:

Jerry thinks the Standard Deviation = 8
The true Standard Deviation = 3.16
Error = |True value - Measured value|
Error = |3.16 - 8|
Error = 4.84
Learn more here: brainly.com/question/18562832
59% of 2302....turn the percent to a decimal...." of " means multiply
0.59(2302) = 1358.18 <==
Lets call the rate at which the first panel absorbs solar energy x:
x = 9/7
To find out how much energy the panel will absorb in a certain number of hours, just multiply x by the time:
In 7 hours, energy = (9/7) * 7 = 9MJ
In 8 hours, energy = (9/7) * 8 = (72/7)MJ
Let's call the rate at which the second panel absorbs solar energy y. Therefore, we can write an equation, in x and y, using the information in the question:
5x + 5y = 41
We know what x is, so 5x = 5 * (9/7) = (45/7):
(45/7) + 5y = 41
5y = 41 - (45/7)
41 is the same as (41*7)/7 = 287/7:
5y = 287/7 - 45/7 = (287-45)/7 = 242/7
Divide both sides by 5 to find the value of y (in MJ absorbed per hours, MJ/h):
y = 242/35 = 6.914285714MJ/h
Let's call the time taken for the new panel to absorb 41MJ t:
ty = 41
We know what y is, so substitute that in and solve:
6.914285714t = 41
t = 41/6.914285714 ≈ 5.929752066 hours
I would like to express this value in the SI unit, which is seconds, s:
5.929752066 * 3600 = 21347.1s