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cricket20 [7]
3 years ago
11

If ( First Image) and (Second Image), then which is true?

Mathematics
2 answers:
zepelin [54]3 years ago
8 0

Im answering this so that u can give the other user brainliest.

Diano4ka-milaya [45]3 years ago
6 0

Answer:

The Second one

Step-by-step explanation:

In the picture above.

I hope that it's a clear solution.

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Write an equation for the proportional relationship shown in the table
Papessa [141]

Answer:

y =74x

Step-by-step explanation:

A proportional relationship is represented by y = kx where x is the independent variable, or input, k is the constant of proportionality, and y is the dependent variable or output.

What do we do to the values in the row for x to get the values in the row of y?

It helps to have x = 1 in this table.

74 = (k)(1)

74 = k

8 0
3 years ago
Jemima was arranging 400 packets of biscuits for a sale. She put 52 packets into a basket and displayed 25% of the remaining pac
stealth61 [152]

Answer:

87% of all the packets of biscuits Jemima displayed on the shelves.

Step-by-step explanation:

400-52=348

so, 348*25%

348*25/100

87

6 0
2 years ago
5a – 10b = 45, when b = 3
balandron [24]


Well, since you have the value of b, the first thing you want to do is substitute that value in for b.

5a - 10(3) = 45

10*3 = 30

5a - 30 = 45

Now, to get the variable by itself (a) you have to + 30 because you have to reverse the subtraction.

5a = 75

Now, you divide by 5 to finish getting a by itself.

a = 15

Hope this helps!

6 0
3 years ago
Read 2 more answers
Please help quickly, if someone answers quickly I'll give them Brainly.
denis-greek [22]
1. A

I hope this helped! This is because the division of numbers and factors are equal to this.
6 0
2 years ago
Read 2 more answers
A market research firm supplies manufacturers with estimates of the retail sales of their products from samples of retail stores
EastWind [94]

Answer:

(52-49) -4.300= -1.300

(52-49) +4.300= 7.300

And the 95% confidence would be :

-1.300 \leq \mu_1 -\mu_2 \leq 7.300

Step-by-step explanation:

We have the following info given from the problem

\bar X_1 = 52 sample mean for this year

s_1= 13 sample deviation for this year

n_1 = 75 random sample selected for this year

\bar X_2 = 49 sample mean for last year

s_2= 11 sample deviation for last year

n_1 = 53 random sample selected for last year

And we want to construct a 95% confidence interval estimate of the difference μ1−μ2, where μ1 is the mean of this year's sales and μ2 is the mean of last year's sales

For this case the formula that we need to use is:

(\bar X_1 -\bar X_2) \pm t_{\alpha/2} \sqrt{\frac{s^2_1}{n_1} +\frac{s^2_2}{n_2}}

The degrees of freedom are given by:

df= n_1 +n_2 -2 = 75+53-2= 126

The confidence level is 0.95 and the significance would be \alpha=0.05 and \alpha/2 =0.025 so then the critical value for this case is :

t_{\alpha/2}= 1.979

The margin of error would be:

ME = 1.979 \sqrt{\frac{13^2}{75} +\frac{11^2}{49}}= 4.300

And the confidence interval would be given by:

(52-49) -4.300= -1.300

(52-49) +4.300= 7.300

And the 95% confidence would be :

-1.300 \leq \mu_1 -\mu_2 \leq 7.300

6 0
3 years ago
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