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3 years ago

If ( First Image) and (Second Image), then which is true?

Mathematics

2 answers:

zepelin [54]3 years ago

8 0

Im answering this so that u can give the other user brainliest.

Diano4ka-milaya [45]3 years ago

6 0

Answer:

The Second one

Step-by-step explanation:

In the picture above.

I hope that it's a clear solution.

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Write an equation for the proportional relationship shown in the table

Papessa [141]

Answer:

y =74x

Step-by-step explanation:

A proportional relationship is represented by y = kx where x is the independent variable, or input, k is the constant of proportionality, and y is the dependent variable or output.

What do we do to the values in the row for x to get the values in the row of y?

It helps to have x = 1 in this table.

74 = (k)(1)

74 = k

8 0

3 years ago

Jemima was arranging 400 packets of biscuits for a sale. She put 52 packets into a basket and displayed 25% of the remaining pac

stealth61 [152]

Answer:

87% of all the packets of biscuits Jemima displayed on the shelves.

Step-by-step explanation:

400-52=348

so, 348*25%

348*25/100

6 0

2 years ago

5a – 10b = 45, when b = 3

balandron [24]

Well, since you have the value of b, the first thing you want to do is substitute that value in for b.

5a - 10(3) = 45

10*3 = 30

5a - 30 = 45

Now, to get the variable by itself (a) you have to + 30 because you have to reverse the subtraction.

5a = 75

Now, you divide by 5 to finish getting a by itself.

a = 15

Hope this helps!

6 0

3 years ago

Read 2 more answers

Please help quickly, if someone answers quickly I'll give them Brainly.

denis-greek [22]

1. A

I hope this helped! This is because the division of numbers and factors are equal to this.

6 0

3 years ago

Read 2 more answers

A market research firm supplies manufacturers with estimates of the retail sales of their products from samples of retail stores

EastWind [94]

Answer:

$(52-49) -4.300= -1.300$

$(52-49) +4.300= 7.300$

And the 95% confidence would be :

$-1.300 \leq \mu_1 -\mu_2 \leq 7.300$

Step-by-step explanation:

We have the following info given from the problem

$\bar X_1 = 52$ sample mean for this year

$s_1= 13$ sample deviation for this year

$n_1 = 75$ random sample selected for this year

$\bar X_2 = 49$ sample mean for last year

$s_2= 11$ sample deviation for last year

$n_1 = 53$ random sample selected for last year

And we want to construct a 95% confidence interval estimate of the difference μ1−μ2, where μ1 is the mean of this year's sales and μ2 is the mean of last year's sales

For this case the formula that we need to use is:

$(\bar X_1 -\bar X_2) \pm t_{\alpha/2} \sqrt{\frac{s^2_1}{n_1} +\frac{s^2_2}{n_2}}$