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cricket20 [7]
3 years ago
11

If ( First Image) and (Second Image), then which is true?

Mathematics
2 answers:
zepelin [54]3 years ago
8 0

Im answering this so that u can give the other user brainliest.

Diano4ka-milaya [45]3 years ago
6 0

Answer:

The Second one

Step-by-step explanation:

In the picture above.

I hope that it's a clear solution.

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What is the solution of x-7= ir+14,
weqwewe [10]

Answer:

x=12

Step-by-step explanation:

put the x at one side and the numbers ar the other

5/2x-3/4x=14+7

10/4x-3/4x=21

7/4x=21

7x=84

x=12

3 0
3 years ago
Based on the Fundamental Theorem of Algebra, how many complex roots does each of the following equations have? Write your answer
mars1129 [50]

Answer:

2, 2, 4, 6, 4

Step-by-step explanation:

Fundamental Theorem of Algebra states that 'An 'n' degree polynomial will have n number of real roots'.

1. The polynomial is given by x(x^2-4)(x^2+16) = 0

So, on simplifying we get that, x(x+2)(x-2)(x^2+16)=0.

Since, degree of polynomial is 5, it will have 5 roots.

This gives us that the roots of the equation are x = 0, -2, 2, 4i and -4i

So, the number of complex roots are 2.

2. The polynomial is given by (x^2+4)(x+5)^2 = 0

Since, degree of polynomial is 4, it will have 4 roots.

Equating them both by zero, (x^2+4)= 0 and  (x+5)^2=0 gives that the roots of the polynomial are x = 2i, -2i, -5, -5.

So, the number of complex roots are 2.

3. The polynomial is given by x^6-4x^5-24x^2+10x-3=0

Since, degree of polynomial is 6, it will have 6 roots.

On simplifying, we get that the real roots of the polynomial are x = -1.75 and x = 4.28.

So, the number of complex roots are 6-2 = 4.

4. The polynomial is given by x^7+128=0

Since, degree of polynomial is 7, it will have 7 roots.

On simplifying, we get that the only real root of the polynomial is x = -2.

So, the number of complex roots are 7-1 = 6.

5. The polynomial is given by (x^3+9)(x^2-4)=0

Since, degree of polynomial is 5, it will have 5 roots.

Simplifying the equation gives (x+2)(x-2)(x+\sqrt[3]{9})(x^2-\sqrt[3]{9x}+9^{\frac{2}{3}})=0

Equating each to 0, we get the real roots of the polynomial is x=-3^{\frac{2}{3}}

So, the number of complex roots are 5-1 = 4

6 0
3 years ago
Read 2 more answers
Can u help me please?
slavikrds [6]
21.W hich value of y makes the following equatoin true?
answer:B
7 0
3 years ago
Without establishing good credit, it would be most difficult to
Elenna [48]

Answer:

It's gonna be C

Step-by-step explanation:

No explanation it's C.

5 0
3 years ago
Theoretical probability is approximated by conducting trials and recording the ratio for the number of occurrences of the event
Art [367]
False.
This is the definition of Experimental probability
5 0
3 years ago
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