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ss7ja [257]
3 years ago
15

Take your time with this. What are the answers for C and D? Will mark Brainliest.

Mathematics
1 answer:
Bumek [7]3 years ago
3 0

Answer:

Step-by-step explanation:

Part C- y=20x+600

Part D- To part D find the equations for all the cities.

Everett- y=15x+550

Chelsea- y=20x+600

Revere- y=50x+300

Since 2030 is 14 years away from 2016 x will equal 14.

Plug in 14 to each of the equations. Whichever has the highest result will be the answer.

Everett- y=15(14)+550 -----> y=760

Chelsea- y=20(14)+600 -----> y=880

Revere- y=50(14)+300 -----> y=1000

Revere will have the most chromebooks.

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Approximate the change in the volume of a sphere when its radius changes from r= 5ft to r= 5.1ft (v(r)= 3/4 pi r^3)?
leva [86]

Answer:

18.03 cubic feet

Step-by-step explanation:

Hello,

Step 1

find the volume of the sphere when radius= 5 ft

v(r)= \frac{3}{4} \pi r^3\\v(5)= \frac{3}{4}\pi (5\ ft)^3\\v(5)= \frac{3}{4}\pi *125\ ft^{3} \\v(5)=294.52\ cubic\ feet\\

Step 2

find the volume of the sphere when radius= 5.1 ft

v(r)= \frac{3}{4}\pi r^3\\v(5.1)= \frac{3}{4} \pi (5.1\ ft)^3\\v(5.1)= \frac{3}{4}\pi *132.651\ ft^{3} \\v(5.1)=312.551\ cubic\ feet\\\\

Step 3

Compare the Volumes to find the change

\frac{v(r_{2})}{v(r_{1})} =\frac{312.551}{294.52} =1.06

the volumen of the sphere with radius = 5.1 is 1.06 times bigger than the first one(r=5)

Now, find the change

change= {v(r_{2})-{v(r_{1})}} \\change=312.551\ cubic\ feet\ -294.52 cubic feet \\ change=18.031\ cubic\ feet

change=18.03 cubic feet

Have a great day.

4 0
3 years ago
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