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4 years ago

Please help.........................

Mathematics

1 answer:

astraxan [27]4 years ago

7 0

The diameter in centimeters (cm) of a human hair is about 0.0025 cm. In terms of scientific notation, it is written as 2.5 x 10^-3 cm

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Solve for x. Round your answer to the nearest tenth. (one decimal place) X=?? degrees

fredd [130]

Answer:

Angle x is congruent with the interior angle opposite side 8 (alternate interior angles)

Use tangent:

tan x = 8/15
x = arctan (8/15)
x = 28.1° (rounded)

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3 years ago

When pricing out a menu, we know it is important to use the Edible a portion Price. What would the effect on your profit margin

Colt1911 [192]

The effect of Edible a portion Price on your profit margin , if we only use the as purchased price to determine our cost and selling price is that it will maximize the profit because it will account for every part of the production.

<h3>What is edible portion cost?</h3>

The portion cost can be calculated by multiplying the cost of a usable kg with the portion size.

This can be represented as : portion cost = (portion size x cost of usable kg)

It should be noted that Edible portion (EP) serves as the portion of food which will be given top the customer after the preparation.

Learn more about profit margin at:

brainly.com/question/8189926

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2 years ago

a bus with 32 passengers stops and picks up 9 more people.at the next stop, s passengers get off.there are 41 passengers left on

Lemur [1.5K]

Answer:

B. B is the answer cause math (Sorry I just want points)

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3 years ago

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Lyrx [107]

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3 years ago

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A tank initially contains 60 gallons of brine, with 30 pounds of salt in solution. Pure water runs into the tank at 3 gallons pe

adoni [48]

Answer:

the amount of time until 23 pounds of salt remain in the tank is 0.088 minutes.

Step-by-step explanation:

The variation of the concentration of salt can be expressed as:

$\frac{dC}{dt}=Ci*Qi-Co*Qo$

being

C1: the concentration of salt in the inflow

Qi: the flow entering the tank

C2: the concentration leaving the tank (the same concentration that is in every part of the tank at that moment)

Qo: the flow going out of the tank.

With no salt in the inflow (C1=0), the equation can be reduced to

$\frac{dC}{dt}=-Co*Qo$

Rearranging the equation, it becomes

$\frac{dC}{C}=-Qo*dt$

Integrating both sides

$\int\frac{dC}{C}=\int-Qo*dt\\ln(\abs{C})+x1=-Qo*t+x2\\ln(\abs{C})=-Qo*t+x\\C=exp^{-Qo*t+x}$

It is known that the concentration at t=0 is 30 pounds in 60 gallons, so C(0) is 0.5 pounds/gallon.

$C(0)=exp^{-Qo*0+x}=0.5\\exp^{x} =0.5\\x=ln(0.5)=-0.693\\$

The final equation for the concentration of salt at any given time is

$C=exp^{-3*t-0.693}$

To answer how long it will be until there are 23 pounds of salt in the tank, we can use the last equation:

$C=exp^{-3*t-0.693}\\(23/60)=exp^{-3*t-0.693}\\ln(23/60)=-3*t-0.693\\t=-\frac{ln(23/60)+0.693}{3}=-\frac{-0.959+0.693}{3}= -\frac{-0.266}{3}=0.088$

5 0

3 years ago